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mario62
2 months ago
9

You have a job as a teacher. Your salary for the first year is $37,185.

Mathematics
1 answer:
tester [12.3K]2 months ago
5 0
a) This represents a geometric sequence. b) c) The salary at the beginning of the fifth year will be $46,945.21. To clarify, my starting salary is $37,185. Should I receive a 6% raise each year, the salary for the following year will be: $37,185 x 1.06 = $39,416.10. Consequently, the salary after the second year will be: $39,416.10 x 1.06 = $41,781.07. Hence, the salary sequence will look like: $37,185, $39,416.10, $41,781.07, and so forth, demonstrating a consistent ratio of r = 1.06 for each term.
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Darryl wants to add enough water to 8 gallons of a 10% bleach solution to make a 5% bleach solution. Which equation can he use t
lawyer [12517]

Response:- 0.8/8+x=5/100

Detailed explanation:

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2 months ago
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An entrepreneur estimates that the total profit (profit = total revenue minus total cost) from his proposed company will be give
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Having no profit indicates that P(x)=0: x³-4x²+3x-12=0
factor this by regrouping: x²(x-4)+3(x-4)=0
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1 month ago
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Evaluate ∫SF⃗ ⋅dA⃗ , where F⃗ =(bx/a)i⃗ +(ay/b)j⃗ and S is the elliptic cylinder oriented away from the z-axis, and given by x2/
Inessa [12570]

Respuesta:

Por lo tanto, la integral de superficie es \pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c.

Explicación paso a paso:

La función dada es,

\vec{F}=\frac{bx}{a}\uvec{i}+\frac{ay}{b}\uvec{j}

Para encontrar,

\int\int_{S}\vec{F}dS 

donde S=A=superficie del cilindro elíptico debemos aplicar el teorema de divergencia, así que,

\int\int_{S}\vec{F}dS

=\int\int\int_V\nabla.\vec{F}dV

=\int\int\int_V(\frac{b}{a}+\frac{a}{b})dV 

=\frac{a^2+b^2}{ab}\int\int\int_VdV

=\frac{a^2+b^2}{ab}\times \textit{Volume of the elliptic cylinder}

=\frac{a^2+b^2}{ab}\times \pi ab\times 2c=\pi (a^2+b^2)c

  • Si el vector unitario \cap{n} está dirigido en dirección positiva (hacia afuera), entonces z=c y,

\int\int_{S_1}\vex{F}.dS_1=\int\int_{S_1}. dA 

=\int\int_{S_1}.dA=0

  • Si el vector unitario \cap{n} está dirigido en dirección negativa (hacia adentro), entonces z=-c y,

\int\int_{S_2}\vex{F}.dS_2=\int\int_{S_2}. -dA 

=\int\int_{S_2}. -dA=0

Por lo tanto, la integral de superficie sin el vector unitario de la superficie es,

\pi(a^2+b^2)c-0-0=\pi(a^2+b^2)c

5 0
2 months ago
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