Mr. Garcia has 15 boys and 10 girls in his math class. He selects two students at random to demonstrate how they solved the day’

It includes the procedures to reach that specific point.
Some of them are arranged incorrectly.
I will label them with letters.

The sequence is:
A: 2x+5=19
B: 2x+5-5=19-5
C: 2x=14
D: 2x/2=14/2
E: x=7


A: initial condition
B: we subtracted 5 from both sides based on the subtraction property of equality
C: perform the subtraction
D: applying the division property of equality (dividing both sides by 2)
E: result of the division

2x + 4

To represent 2x + 4, the following is required:

2 positive x-tiles corresponding to 2x.

4 positive unit tiles for the value of 4.

3x + (-1)

To illustrate 3x + (-1), you will need:

3 positive x-tiles to depict 3x.

1 negative unit tile to signify (-1).

Result:

6.1°; 425.86 m.

Step-by-step breakdown:

The information provided states that the airplane is at an altitude of 5.7 miles above ground level, while the "radius of Earth is about 4000 miles." Thus,

θ = 2 × cos^-1 (a/ (a + b)), where a = 4000 miles, and b = 5.7 miles.

θ = 2 × cos^-1 (4000/ (4000 + 5.7)) = 6.1°.

To calculate the distance in meters:

Change in distance = 6.1° /360° × 2π × 4000 miles = 425.86 meters.

Consequently, BD⌢ measures at 6.1° and the distance corresponding to this section of Earth is 425.86 meters.

Triangle XYZ is an equilateral triangle, meaning the sector's central angle measures 120 degrees, which is equivalent to 2π/3 radians. To find the area of a sector corresponding to a central angle β, we use the formula A = (1/2)r²*β, where β is expressed in radians. For this sector, the area calculation is A = (1/2)*2²*(2π/3) = 4π/3 square units.

Answer:

5.25ft below the waterline

Step-by-step explanation:

1. I entered the given equation into a graphing calculator (I use Desmos) and substituted "t" with "x" since it’s easier that way.

2. A graph appeared. To find the initial position of the paddle, I checked where it was at t=0, which is the y-intercept. It shows it’s at -5.25, indicating it sits 5.25 below the surface of the water.