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Blababa
12 days ago
10

Every $4,000 spent on cable TV will reach 160 fans while every $2,750 spent on radio ad will reach 125 fans. A stadium has estab

lished a goal of reaching 200,000 fans with it's advertisement. It has an advertising budget of $3 million. Which advertising option should the stadium use to meet the goal?
Mathematics
1 answer:
AnnZ [9K]12 days ago
8 0

Answer:

Neither of the two advertising choices achieves the objective.

Step-by-step explanation:

For every $4,000 allocated to cable TV, 160 fans will be reached.

Thus, to meet the target of 200,000 fans, it would require \frac{4000 \times 200000}{160} = 5000000 dollars which amounts to $5 million, exceeding the budget of $3 million.

Similarly, each $2,750 invested in radio ads will connect with 125 fans.

Consequently, achieving the target of 200,000 fans would necessitate \frac{2750 \times 200000}{125} = 4500000 dollars which totals $4.5 million, which also surpasses the $3 million budget.

Therefore, neither of the two advertising choices achieves the objective. (Answer)

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Step-by-step analysis:

Let x denote the beads with Jenny and y for Maia.

The information provided states that Maia possesses 2064 beads more than Jenny, which can be represented mathematically as:

y=x+2064...(1)

Additionally, after Maia made a necklace with 144 beads, she had five times more beads than Jenny.

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A) Since Maia had 2064 beads more than Jenny before using 144 beads, we calculate her final bead count by subtracting 144 from 2064.

\text{Number of beads Maia had more than Jenny in the end}=2064-144

\text{Number of beads Maia had more than Jenny in the end}=1920

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B) To solve this system of linear equations, we will utilize the substitution method.

By inserting equation (1) into equation (2), we arrive at:

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1920=4x

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\frac{1920}{4}=\frac{4x}{4}

480=x

Now, we'll substitute x=480 into equation (1) to isolate y.

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