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taurus
2 days ago
14

A recent study showed that women who lived near a freeway had an unusually high rate of rheumatoid arthritis. Sarah said, "They

should move away from freeways." Select the correct fallacy in Sarah's reasoning?
Mathematics
2 answers:
lawyer [9.2K]2 days ago
6 0

Answer:

Step-by-step explanation:

Sarah's reasoning reflects an adherence to Pitfalls 5 and 6.

Association in statistics does not equate to causation; there must be a robust basis for claiming cause and effect. Even if such evidence were presented, it is erroneous to extend group results to individuals.

babunello [8.4K]2 days ago
5 0

Answer:

Step-by-step explanation:

The full question is outlined below:

A recent study indicated that women living near a freeway experienced a notable rise in rheumatoid arthritis cases. Sarah suggested that they should relocate away from freeways.

Upon selecting any answer perceived as correct, the following fallacies stood out:

Pitfall 1: Conclusions from Small Samples unchecked

Pitfall 3: Conclusions from Rare Events checked

Pitfall 4: Poor Survey Methods checked

Pitfall 5: Assuming a Causal Link checked

Pitfall 6: Generalization to Individuals

Sarah falls under Pitfalls 5 and 6. Just because a statistical correlation exists does not imply causation. There is a need for substantive proof supporting cause and effect; furthermore, applying group findings to individuals lacks validity. Without sufficient evidence, one cannot generalize outcomes.

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Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k. k = ______ Graph of two lines. f of x equa
lawyer [9240]

Solution:

We know, g(x) = f(x) + k --------(1)

It is given that f(x) = \frac{1}{3}(x+2)

and g(x) = \frac{1}{3}(x+5)

Substituting f(x) and g(x) into equation (1):

→ \frac{1}{3}(x+5) = \frac{1}{3}(x+2) + k

→ \frac{1}{3}[x+5-x-2] = k

→ k = \frac{1}{3} \times 3=1

Thus, the value of k is 1.

7 0
26 days ago
A community center charges x dollars for a summer activity if individuals are signed up before the day of the activity. Individu
lawyer [9240]

Answer:

The correct answer appears to be A, please inform me if that is incorrect.

Step-by-step explanation:

5 0
16 days ago
Read 2 more answers
What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [9240]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
19 days ago
The random variable X, representing the number of cherries in a cherry puff, has the following probability distribution:x: 4 - 5
Leona [9271]

Answer:

Step-by-step explanation:

The probability distribution for the random variable X is provided.

X 4 5 6 7 Total

P 0.2 0.4 0.3 0.1 1

x*p 0.8 2 1.8 0.7 5.3

x^2*p 3.2 10 10.8 4.9 28.9

a) The expected value E(X), representing the mean of X, equates to 5.3.

Var(x) = 28.9-5.3^2=0.81

Standard deviation is the square root of the variance, which amounts to 0.9.

------------------------------------

b) For the mean of the sample, we find:

Mean = 5.3

Variance = var(x)/n = \frac{0.81}{{36} } \\=0.0225

c) P(\bar X

3 0
21 day ago
AA3+2=AAA<br>CC6+6=CBB<br> ABC= ?
Zina [9171]
From AA3+2=AAA, it follows that 3+2 equals A, so A must be 5.
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1 month ago
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