A circular pipe of 25-mm outside diameter is placed in an airstream at 25 °C and 1-atm pressure. The air moves in cross flow ove

Answer:

This is the solution code in Python:

1. alphabets = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J']
3. user_input = input("Enter number of rows and columns: ")
4. myArr = user_input.split(" ")
5. num_rows = int(myArr[0])
6. num_cols = int(myArr[1])
8. seats = []
10. for i in range(num_rows):
11. row = []
12. for j in range(num_cols):
13. row.append(alphabets[j])
14. seats.append(row)
16. output = ""
18. for i in range(len(seats)):
19. for j in range(len(seats[i])):
20. output += str(i + 1) + seats[i][j] + " "
22. print(output)

Explanation:

Initially, we create a small list of alphabets from A to J (Line 1).

We then request the user to enter the number of rows and columns (Line 3). Given that the input comes as a string (e.g., "2 3"), we utilize the split() method to separate the numbers into individual items in a list (Line 4). The first item (row number) is assigned to variable num_rows, while the second item (column number) goes to num_cols.

Subsequently, we construct the seats list with a nested for-loop (Lines 10-15). Once the seats list is formed, another nested for-loop generates the required output string as per the question (Lines 19-21).

Finally, the output is printed (Line 23). For example, an input of 2 3 results in the output:

1A 1B 1C 2A 2B 2C

Response:

a) 4 kg/s

b) 99.61 °C

Rationale:

Refer to the pictures provided.

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are special functions for use with the insertion (<<) and extraction (>>) operators on C++ stream objects, while the 'cout' statement outputs content to the standard output device in C++ programming.

setw: specifies the minimum width of the output field

setprecision: defines the number of decimal places for floating-point value formatting.

fixed: sets the format flag for floating-point streams.

left: left-aligns the output.

A) This statement shows the number 34.789 in a field that provides eight character spaces with two decimal precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) Here, the number 7.0 is displayed within six spaces with three decimal precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) This command prints 5.789e+12 in fixed-point format.  cout<<fixed<<5.789E12;

D) This statement left-aligns the number 67 across a field of six spaces. cout<<left<<setw(7)<<67;

Answer:

The power of the pump is 23.09 kW.

Explanation:

Parameters

gravitational constant,

mass flow rate,

flow density,

efficiency of the pump,

output gauge pressure,

input gauge pressure,

cross-sectional area of output pipe,

cross-sectional area of input pipe,

height of discharge, (evaluated at pump’s maximum height of 1.22 m)

input height,

hydraulic power of the pump,

Initially, the volumetric flow (Q) needs to be determined

Next, compute the velocity (v) for both input and output

Subsequently, the total head (H) can be calculated

Finally, the computation of pump power is done as follows