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2 months ago

Tim has an after-school delivery service that he

1 answer:

3 0

Tim operates a delivery service for local retailers, charging $1.25 for deliveries within 1.5 miles, $1.70 for distances from 1.5 miles to less than 1.75 miles, $2.15 for distances from 1.75 miles to less than 2 miles, and so on. If he increases his prices by 10%, how much will he charge for a 3 1/8 mile delivery? The cost for moving an extra 1/4 mile (between 1.75 miles and 1.5 miles) is $0.45 (calculated as $1.70 - $1.25). So, with a 10% hike, this charge becomes 1.1 × $0.45 = $0.495. Here would be Tim's adjusted rates: $1.25 for 1.5 miles, $1.745 for 1.5 to 1.75 miles, $2.24 for 1.75 to 2 miles, $2.735 for 2 to 2.25 miles, $3.23 for 2.25 to 2.5 miles, $3.725 for 2.5 to 2.75 miles, $4.22 for 2.75 to 3 miles, and $4.715 for 3 miles to 3.25 miles. Therefore, delivering a package 3 1/8 miles would cost $4.715.

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An artist is creating a sculpture using bendable metal rods of equal length. One rod is formed into the shape of a square and an

zzz [12365]

Refer to the image below. Note that the perimeters are identical since a single rod constitutes the perimeter, and since all rods are of equal length.

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1 month ago

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The hypotenuse of a right triangle has a length of 14 units and a side that is 9 units long. Which equation can be used to find

Svet_ta [12734]

Response: Using the Pythagorean theorem, we can set up the equation as 14^2=9^2+x^2

-9^2 -9^2

Thus, our equation simplifies to

x^2=14^2-9^2

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2 months ago

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Given that Ray E B bisects ∠CEA, which statements must be true? Select three options. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB =

tester [12383]

Answer:

Attached is the question in consideration.

$m\angle CEA =90 \ (deg)$

$m\angle BEF=135\ (deg)$

$\angle CEF$ forms a straight line.

$\angle AEF$ depicts a right triangle.

The options $1,4,5,6$ represent the correct answers.

Step-by-step explanation:

⇒ Given that $\ ray\ AE$ is ⊥ $FEC$ it constitutes a right triangle, leading to $m\angle CEA =90\ (deg)$ .

⇒ The measure for $\angle BEF =135\ (deg)$ equals $\angle BEF =\angle AEB +\angle AEF = (45+90)=135\ (deg)$ as $\angle AEB$ bisects $\angle AEC$ , implying that $\angle AEB$ is half of $\angle AEC$ , thus $\angle AEB = 45\ (deg)$ .

⇒ $\angle CEF$ represents a straight line, as the angle measures across it yield $180\ (deg)$ .

⇒ The angle measure for $\angle AEF = 90\ (deg)$ is derived from the linear pair concept.

Since $\angle CEA + \angle AEF = 180\ (deg)$ , inserting the values of $m\angle CEA =90\ (deg)$ leads to $\angle AEF = 90\ (deg)$ .

The other two options are incorrect as:

$m\angle CEF=m\angle CEA + m\angle BEF = (90+135)=225$

it surpasses $180\ (deg)$ while $\angle CEF$ is a

straight line.

Also, $m\angle CEB=2(m\angle CEA)$ is inaccurate.

As $\angle CEA = 90\ (deg)$ and $\angle CEB=45\ (deg)$

Thus, we have a total $4$ valid answers.

The confirmed options are $1,4,5,6$ .

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2 months ago

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A frog is sitting exactly in the middle of a board that is five feet long. Every ten seconds he jumps one foot to the left or on

PIT_PIT [12445]

Answer:

Given that the frog jumps every 10 seconds

(using digits from a random number table)

It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

Step-by-step explanation:

A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.

Every 10 seconds, the frog jumps left or right.

If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.

If it jumps as LLRLL, it will jump off the board after fifty seconds.

Given that the frog jumps every 10 seconds

(using digits from a random number table)

It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.

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3 months ago

What is the factored form of the polynomial x2 - 16x + 48

PIT_PIT [12445]

(x - 12) (x - 4) is the answer

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2 months ago

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