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Stells
12 days ago
15

Tim has an after-school delivery service that he

Mathematics
1 answer:
lawyer [9.2K]12 days ago
3 0
Tim operates a delivery service for local retailers, charging $1.25 for deliveries within 1.5 miles, $1.70 for distances from 1.5 miles to less than 1.75 miles, $2.15 for distances from 1.75 miles to less than 2 miles, and so on. If he increases his prices by 10%, how much will he charge for a 3 1/8 mile delivery? The cost for moving an extra 1/4 mile (between 1.75 miles and 1.5 miles) is $0.45 (calculated as $1.70 - $1.25). So, with a 10% hike, this charge becomes 1.1 × $0.45 = $0.495. Here would be Tim's adjusted rates: $1.25 for 1.5 miles, $1.745 for 1.5 to 1.75 miles, $2.24 for 1.75 to 2 miles, $2.735 for 2 to 2.25 miles, $3.23 for 2.25 to 2.5 miles, $3.725 for 2.5 to 2.75 miles, $4.22 for 2.75 to 3 miles, and $4.715 for 3 miles to 3.25 miles. Therefore, delivering a package 3 1/8 miles would cost $4.715.
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Part A

To identify the values of x that make 2x−1 positive

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⇒ 2x > 1

⇒ x > \frac{1}{2}

As a result, for any x greater than \frac{1}{2}, the expression 2x-1 is positive

Part B

To find values of y making 21−37 negative

⇒ 21-3y < 0

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⇒ 7 < y

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Part C

To identify values of c that digit 5−3c greater than 80

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6 days ago
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To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
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23 hours ago
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Answer:

Option C is the right choice.

Step-by-step explanation:

The given coordinates define a rectangle, and our objective is to show that the diagonals JL and KM are congruent.

We know that rectangles possess four right angles.

To prove the congruence of the diagonals JL and KM, we will utilize the Pythagorean theorem.

In triangle KLM, KL has a length of b units while LM has a length of a units. By applying the Pythagorean theorem \sqrt(a^{2}+b^{2})=KM

In triangle JML, JM is b units long, and LM remains a units long. We again can apply the Pythagorean theorem \sqrt(a^{2}+b^{2})=JL

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27 days ago
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Response:

The data shows skewness, with the minimum amount of crackers in a pack being 7

Detailed explanation:

Hello,

Firstly, the question lacks completeness due to missing information from the box plot, which I have provided to assist you in answering your inquiry.

Considering the details from the attached image, a symmetric distribution would be centered evenly, but that is not the case here.

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