Answer:
1. What are the amplitude and period of the sine function that indicates the positioning of the band members as they start performing?
Answer: The amplitude is 80 ft and the period is 60 ft.
2. Edna, seated in the stands, faces Darla and notices that the sine curve starts rising from the left edge of the field. What is the equation for the sine function representing the arrangement of band members at the beginning of their performance?
Answer: y = 80cos(x*π/30)+80
3. When the band starts playing, the members move away from the edges, and the sine curve changes to start decreasing at the far left. Darla remains in her position. Now the sine curve is half as tall as it originally was. What is the equation for the updated sine curve depicting the band members' positions?
Answer: y = 40cos(x*π/30)+80
4. Finally, the entire band shifts closer to the edge of the football field, causing the sine curve to now position itself in the lower half of the field from Edna’s perspective. What is the equation for this sine curve reflecting the band members' positions after these adjustments?
Answer: y = 40cos(x*π/30)+40
Step-by-step explanation:
Answer:
∠ R 
90°
Explicación paso a paso:
Dado que en el triángulo RST
Ahora, según la condición, un ángulo es mayor que la suma de los otros dos ángulos.
En un triángulo, la suma de los tres ángulos es 180°
Por lo tanto, si un ángulo mide 90°, la suma de los otros dos debe ser igual a 90°
Y si uno de los ángulos es de 90°, solo los otros dos pueden ser de 45° cada uno.
Aquí suponiendo que el ángulo s = ángulo T = 30°, entonces con esta condición el ángulo r sería de 120°, que es mayor que 90°.
De lo anterior, se concluye que
Para,
∵ ∠ R = 120°, por lo tanto es mayor que 90°.
Es decir, ∠ R 90°
Respuesta
To determine the values of b that fulfill 3(2b+3)^2 = 36
we start with
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
Next, take the square root of both sides
(2b+3)} = (+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Thus,
the solutions for b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Area of a rectangle = length x width
For this postcard:
length = 4 in
width = (3+b) in
area = 24 in^2
Substitute into the area formula:
24 = 4 x (3+b)
24 = 12 + 4b
24 - 12 = 4b
12 = 4b
b = 3 in
Therefore:
the length of the postcard = 4 inch
the width of the postcard = b+3 = 3 + 3 = 6 inch
Answer:
Step-by-step explanation:
To solve for v, reverse the operations performed on it, starting with the equation provided. Here, v is affected by:
- being multiplied by t
- subtracting gt^2 from the result
To start, we first need to add gt^2 back to the equation to counteract the subtraction:
h + gt^2 = vt
Next, we undo the multiplication by dividing the entire expression by the coefficient of v:
(h + gt^2)/t = v
