Sasha sets a goal to read 5 minutes longer than each previous day for 30 days. On the first day, Sasha reads for 20 minutes. The
2 answers:
Let 
signify the number of pages that Sasha reads on day n
for instance,
represents the number of pages read on day 7.
On the first day, Sasha reads for 20 minutes, which translates to
minutes
minutes. Since she adds 5 minutes on each subsequent day
, we can compile the following enumeration:
Thus, it is clear that in 30 days, Sasha reads:
+
+
+...+
=
= 20 +(20+5)+(20+5*2)+(20+5*3)+...+(20+5*29)
In total, there are 30 sets of twenty plus 5 times the sum of integers from 1 to 29, simplifying to 5.
The sum of integers from 1 to 29 is calculated with Gauss's formula as (29*30)/2 = 435
. Therefore, the overall total is 20*30+435=600+435=1035 (minutes)
Note: Gauss's formula states that 1+2+3+...+(n-1)+n = n(n+1)/2
Result: 1035 minutes
for instance,
On the first day, Sasha reads for 20 minutes, which translates to
, we can compile the following enumeration:
Thus, it is clear that in 30 days, Sasha reads:
= 20 +(20+5)+(20+5*2)+(20+5*3)+...+(20+5*29)
In total, there are 30 sets of twenty plus 5 times the sum of integers from 1 to 29, simplifying to 5.
The sum of integers from 1 to 29 is calculated with Gauss's formula as (29*30)/2 = 435
. Therefore, the overall total is 20*30+435=600+435=1035 (minutes)
Note: Gauss's formula states that 1+2+3+...+(n-1)+n = n(n+1)/2
Result: 1035 minutes
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Step-by-step explanation:
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Please refer to the attached document for a comprehensive resolution and step-by-step explanation
Answer:
The repair of the stretch of road will require weeks to finish.
Provided:
Length of the roads needing repair =
Length of the road workers can fix in a week =
To ascertain how many weeks it will take to mend this road stretch.
Solution:
Worker's road repair rate = per week.
Overall road length to repair =The time required to repair
of road by the workers can be calculated: ⇒
When dividing mixed numbers, we change them first into fractions.
To compute fraction division, we take the reciprocal of the divisor and substitute division with multiplication:
⇒
We revert the fraction back into a mixed number.
Thus, it will take weeks to complete the road repair task.