75,88,90,96,98,100
minimum = 75
Q1 = 88.....this indicates the start of the box
Q2 (the median) = (90 + 96) / 2 = 186/2 = 93....this signifies the line within the box
Q3 = 98....this indicates the end of the box
maximum = 100
88_93______98
75_______| | |___100
|___|_______|
Answer:
160/1001, 175/1001
Step-by-step explanation:
i) We calculate:
₈C₁ methods to select 1 new camera from a selection of 8
₆C₃ methods to select 3 refurbished cameras from a selection of 8
₁₄C₄ methods to select 4 cameras from the total of 14 cameras
The probability formula is:
P = ₈C₁ ₆C₃ / ₁₄C₄
P = 8×20 / 1001
P = 160 / 1001
P ≈ 0.160
ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:
P = ₆C₄ / ₁₄C₄
P = 15 / 1001
Therefore, the combined probability is:
P = 160/1001 + 15/1001
P = 175/1001
P ≈ 0.175
Answer:
La conclusión sobre p utilizando una desigualdad de valor absoluto es
Explicación paso a paso:
Según el enunciado, nos informan que
La proporción de la muestra es 
El margen de error es 
El intervalo de confianza se representa matemáticamente como
=> 
=>
