<span><span>Center coordinates: (x0, y0, z0)</span></span> and radius r.
<span>The equation of the sphere is:</span>
<span>(x - x0)^2 + (y - y0)^2 + (z - z0)^2 = r^2</span>
Mr. Rowley
16:14
Ms. Rivera
64:60
Upon simplifying 64:60, it becomes 16:15.
64/4 = 16
60/4 = 15
They are not equivalent since Ms. Rivera holds 1 more exit ticket than Mr. Rowley.
The equation representing the circle centered at (-27, 120) that passes through the origin is:

Solution:
The general equation of a circle is expressed as:

Where,
(a, b) denotes the center of the circle
r signifies the radius
Given the center as (-27, 120)
Thus;
a = -27
b = 120
Considering it intersects the origin, meaning (x, y) = (0, 0)
Substituting (a, b) = (-27, 120) and (x, y) = (0, 0) into the equation

Input
= 15129 and (a, b) = (-27, 120) into the equation

Hence, the equation characterizing the circle is determined