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LuckyWell
17 days ago
13

Two satellites, X and Y, are orbiting Earth. Satellite X is 1.2 × 106 m from Earth, and Satellite Y is 1.9 × 105 m from Earth. W

hich best compares the satellites? Satellite X has a greater period and a faster tangential speed than Satellite Y. Satellite X has a greater period and a slower tangential speed than Satellite Y. Satellite X has a shorter period and a faster tangential speed than Satellite Y. Satellite X has a shorter period and a slower tangential speed than Satellite Y.
Physics
2 answers:
Sav [2.8K]17 days ago
8 0
B
Yuliya22 [2.9K]17 days ago
4 0
Satellite X exhibits both a longer period and a reduced tangential speed compared to Satellite Y.
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Heat is allowed to flow from the heat source of a heat engine at 425 K to a cold sink at 313 K. What is the efficiency of the he
Keith_Richards [2911]
I presume that the engine operates under a Carnot cycle, which allows for maximum efficiency.

Assuming this, the Carnot cycle's efficiency can be expressed as
\eta = 1- \frac{T_{cold}}{T_{hot}}
where
T_{cold} represents the temperature of the cold sink
T_{hot} and

signifies the temperature of the heat source.
\eta=1- \frac{313 K}{425 K}=0.264 = 26.4 \%In this scenario, the cold sink temperature is 313 K, while the heat source temperature is 425 K; thus, we can calculate the engine's efficiency as
[[TAG_15]]
3 0
21 day ago
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Martha was leaning out of the window on the second floor of her house and speaking to Steve. Suddenly, her glasses slipped from
serg [3231]
The height from which the glasses fell is s = 23.72 m and the impact speed is v = 21.56 m/s². Explanation: Using the time taken to hit the ground (t) = 2.2 seconds, we can apply the formula s = u t + 0.5 g t² with initial velocity u = 0 m/s and g = 9.8 m/s²: s = 0 + 0.5 × 9.8 × 2.2², resulting in s = 23.72 m. For the impact velocity, we use the equation v = √(2gh), yielding v = √(2 × 9.8 × 23.72) = √464.912, leading to v = 21.56 m/s².
6 0
15 days ago
A parallel-plate capacitor is constructed of two square plates, size L×L, separated by distance d. The plates are given charge ±
inna [2740]

Answer: A) 2 B) 4 C) 1

Explanation:

The electric field associated with a parallel-plate capacitor is defined as:

A) E=Q/(L^2 * ε0); if we double the charge, the resultant electric field becomes twice as strong as its initial value.

B) Referring to the earlier electric field expression, if the plate size is doubled, the final electric field will be a quarter of the original strength.

C) If the separation distance between the plates is increased twofold, the resulting electric field remains unchanged from its initial state.

3 0
25 days ago
At a location where the acceleration due to gravity is 9.807 m/s2, the atmospheric pressure is 9.891 × 104 Pa. A barometer at th
serg [3231]

Answer:

8616.7468 \ kg/m^3

Explanation:

The measurement of pressure is indicated as p=\rho gh where p denotes the pressure, \rho signifies density, and h represents height

Given values include pressure p=9.891\times 10^4\ Pa, gravity's acceleration g=9.9870\ m/sec^2, and height =1.163 m

\rho =\frac{p}{gh}=\frac{9.891\times 10^4}{9.870\times 1.163}=8616.7468 \ kg/m^3

5 0
19 days ago
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In an amusement park rocket ride, cars are suspended from 3.40-m cables attached to rotating arms at a distance of 5.90 m from t
ValentinkaMS [3097]

Answer:

The rotational angular speed is measured at 1.34 rad/s.

Explanation:

Considering the following parameters,

Length = 3.40 m

Distance = 5.90 m

Angle = 45.0°

We are tasked with finding the angular speed of rotation

Using the balance equation

Horizontal component

T\cos\theta=mg

T=\dfrac{mg}{\cos\theta}

Vertical component

T\sin\theta=m\omega^2 r

Substituting the tension value

mg\tan\theta=m\omega^2(d+L\sin\theta)

\omega=\sqrt{\dfrac{g\tan\theta}{(d+L\sin\theta)}}

Substituting the value into the equation

\omega=\sqrt{\dfrac{9.8\tan45.0}{5.90+3.40\sin45.0}}

\omega=1.34\ rad/s

Thus, the angular speed of rotation computes to 1.34 rad/s.

7 0
1 month ago
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