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ella
4 days ago
15

Your friend states in a report that the average time required to circle a 1.5-mi track was 65.414 s. This was measured by timing

7 laps using a clock with a precision of 0.1 s. How much confidence do you have in the results of the report? Explain.
Physics
1 answer:
Yuliya22 [2.9K]4 days ago
5 0
The average time per lap was determined by timing seven laps and averaging the total time over seven. It’s noted that the precision is 0.1 seconds, indicating accuracy to one decimal place. Therefore, the true value might fluctuate between 457.800 seconds and 457.899 seconds, suggesting that lap times could range from 65.400 seconds to 65.414 seconds. Hence, the recorded time of 65.414 seconds has a maximum error of 0.021%, indicating that the measurement is fairly precise.
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What is the gauge pressure of the water right at the point p, where the needle meets the wider chamber of the syringe? neglect t
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Details that are not provided: the problem figure is included.

We can address the exercise by applying Poiseuille's law. This law indicates that for a fluid flowing in a laminar manner within a confined pipe,

\Delta P = \frac{8 \mu L Q}{\pi r^4}

where:

\Delta P represents the pressure difference across the two ends

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L signifies the length of the pipe

Q=Av indicates the volumetric flow rate, where A=\pi r^2 is the cross-sectional area of the tube and v refers to the fluid's velocity

r stands for the pipe's radius.

This law can be utilized for the needle, allowing us to compute the pressure difference between point P and the needle's end. In this scenario, we have:

\mu=0.001 Pa/s is the dynamic viscosity of water at 20^{\circ}

L=4.0 cm=0.04 m

Q=Av=\pi r^2 v= \pi (1 \cdot 10^{-3}m)^2 \cdot 10 m/s =3.14 \cdot 10^{-5} m^3/s

and r=1 mm=0.001 m

Substituting these values into the formula yields:

\Delta P = 3200 Pa

This pressure difference specifies the value between point P and the needle's termination. As the end of the needle is under atmospheric pressure, the gauge pressure at point P, relative to atmospheric pressure, is exactly 3200 Pa.

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Answer:

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