The space probe must be able to recognize 7 distinct command types.
The number of combinations that can be encoded using n bits is 2^n. Thus, the minimum number of bits required to encode at least 7 different commands would be:
2^n > 7
2^n > 2^2.80
n > 2.80
n=3
A minimum of 3 bits is required
Answer:
I’d say it’s moderate in my opinion
Step-by-step explanation:
I might not be correct, so it’s best to wait for another person's input if my answer isn’t what you seek
Answer:
ACE = ECD is the solution
Step-by-step explanation:
Given that the salt concentration in a 125 ml salt solution is at 20%, it indicates a salt to water ratio of 20:80, which simplifies to 1:4.
Consequently, the salt quantity in the 125 ml 20% solution can be calculated as 20% of 125, yielding 0.2 x 125 = 25 ml, and therefore, the water content amounts to 125 - 25 = 100 ml.
When adding 25 ml of water to this 20% salt solution, the total water becomes 100 + 25 = 125 ml while the salt quantity remains at 25 ml.
Thus, the new total volume of the solution is 125 + 25 = 150 ml, leading to a salt proportion in the updated mixture of 25/150 = 0.1667.
As a result, the concentration of the new solution <span>after mixing 25 ml of water with 125 ml of a 20% salt solution is 16.67%</span>
Answer:
Step-by-step explanation:
First, we determine v and a as:
Subsequently, we compute the cross product and substitute it into the formula for k
a(t) X v(t) = (0,0,2)
| a(t) X v(t) | = 2
Thus, we conclude
I trust this is of assistance to you
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