Since m∠abe = 2b, and angle abe consists of angles abf and ebf, we can write:
m∠abe = m∠abf + m∠ebf
To find m∠ebf, rearrange:
m∠ebf = m∠abe - m∠abf
Substitute the given expressions:
m∠ebf = 2b - (7b - 24)
Simplify:
m∠ebf = 2b - 7b + 24
m∠ebf = -5b + 24.
The result I found is 32.761%. Percentage represents any fraction expressed out of 100. It's calculated using the formula: If A is to be expressed as a percentage of B, the formula is A/B * 100. In this case, the paid price for the sweater is $36.20 and the original price is $90.50. We endeavor to find out what percentage reflects the sale price of the sweater. Mathematically, this can be framed as what is 36.20% of 90.5, which translates to (price paid/original price) * 100, and mathematically results in ($36.20/$90.50) * 100 = 32.761. Thus, this indicates that the sweater was sold for 32.761% off its original price.
Answer:
Step-by-step explanation: The error made by the student was dividing the wins by the losses.
The student should have divided the wins by the total number of games played.
Initially, the student ought to have summed 20 and 10 to conclude there were 30 games in total.
The likelihood of selecting one girl is calculated as
. This is based on having 5 girls within a total of 12 students, and the probability of an event can be expressed as:
.
Using the same reasoning, for the next student, we have reduced the number of students by 1, leading to 11 possible outcomes instead of 12, giving us:
, which represents the probability of selecting a boy as the second choice.
Lastly, the probability of choosing a girl for the third selection follows the same logic and is given as:
.
However, we must combine these individual probabilities to determine the likelihood of this specific sequence of selections occurring:

This simplifies to:

Answer:
a. 0.68 or 68%
b. 0.08 or 8%
c. 0.32 or 32%
Step-by-step explanation:
The probability of contacting the client on the first call is 60%
The likelihood of reaching the client on the second call is 20%
a. The chance of the manager successfully connecting with her client within two calls is the sum of the chances for one or two calls:

b. The probability that the manager connects during the second call but not the first is:

c. The probability that the manager fails to connect in two consecutive calls (requiring more calls) is P(X>2):
