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svetlana
13 days ago
14

Chris buys 8 more Ninja Turtles than Star Wars action figures. The Ninja Turtles cost $7 each and the Star Wars cost $9 each. Wr

ite an expression to model this situation, using S for Star Wars.
Mathematics
1 answer:
Svet_ta [12.7K]13 days ago
4 0
Total Cost, C = $(16S + 56). Step-by-step explanation: Chris purchases 8 more Ninja Turtles than Star Wars action figures. The cost per Ninja Turtle is $7, while each Star Wars figure costs $9. If we let S represent the number of Star Wars figures bought, then the number of Ninja Turtles becomes S + 8. The cost for S Star Wars figures is $9S. Similarly, for (S + 8) Ninja Turtles, the total cost is $(7S + 56). Therefore, the overall Total Cost is represented by the sum of the costs for both types of figures, leading to the Total Cost being expressed as C = 9S + (7S + 56).
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What is the solution to –2|2.2x – 3.3| = –6.6? x = –3 x = 3 x = –3 or x = 0 x = 0 or x = 3
babunello [11817]

x = 3

-2 | 2.2(3) - 3.3 | = -6.6

-2 | 6.6 - 3.3 | = -6.6

-2 | 3.3 | = -6.6

-2 * 3.3 = -6.6

-6.6 = -6.6

6 0
22 days ago
Read 2 more answers
Find the standard deviation of the following data. Answers are rounded to the nearest tenth. 5, 5, 6, 12, 13, 26, 37, 49, 51, 56
Inessa [12570]

Response:

24.2 (rounded to the nearest tenth)

Detailed breakdown:

The data type involved is ungrouped

standard deviation =√ [∑ (x-μ)² / n]

average (μ)=∑x/n

           = \frac{5+5+6+12+13+26+37+49+51+56+56+84}{12}

          =33.3

For the values 5, 5, 6, 12, 13, 26, 37, 49, 51, 56, 56, 84, the x-μ results will be

                   -28.3, -28.3, -27.3, -21.3, -7.3, 3.7, 15.7,17.7, 22.7,22.7,50.7

Calculating (x-μ)² gives: 800.89, 800.89, 745.29, 453.69, 53.29, 13.69, 246.49, 313.29, 515.29, 515.29, 2570.49

Then, ∑ (x-μ)² results in = 7028.59

Thus, standard deviation = √(7028.59 / 12)

                      =24.2

     

6 0
14 days ago
The bus routes in a city run on average every 15 minutes. The route times can vary by three minutes. Which absolute value equati
AnnZ [12381]

Response:

Max = 18\ mins

Min = 12\ mins

Step-by-step explanation:

Information given:

Time = 15\ mins

Variation = 3\ mins

Objective:

Calculate the maximum and minimum values

The max value is found as follows:

Max = Time + Variation

Max = 15\ mins + 3\ mins

Max = 18\ mins

The min value is identified as follows:

Min = Time - Variation

Min = 15\ mins - 3\ mins

Min = 12\ mins

3 0
1 month ago
Five more than twice a number is three times the difference of that number and two. What is the number.
Zina [12379]

Response:

2(3-n)+5.

Clarification:

Twice a number plus five equals three times the difference between that number and two. "More" indicates addition, hence twice the number is represented as multiplying N (or whatever variable) with the determination that it equals three times the reduction of that number and two.

5 0
1 month ago
The idle time for taxi drivers in a day are normally distributed with an unknown population mean and standard deviation. If a ra
Svet_ta [12734]

Answer:

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Hence, in this case, the 98% confidence interval would be (163.626;180.374)    

Step-by-step breakdown:

Previous concepts

A confidence interval represents a range that is likely to encompass a population value within a specific confidence level, typically expressed as a percentage whereby a population mean falls between an upper and lower limit.

The margin of errorindicates the span of values surrounding the sample statistic in a confidence interval.

A normal distributionillustrates a probability distribution that is symmetrical around the mean, signifying that values near the mean occur more frequently than those farther away from it.

\bar X=172 denote the sample mean

\mu population mean (the variable of interest)

s=16 signifies the sample standard deviation

n=23 represents the sample size  

The solution to the query

The equation for the confidence interval of the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

To determine the critical value t_{\alpha/2}, we first need to calculate the degrees of freedom, which is expressed as:

df=n-1=23-1=22

Since the confidence level is 0.98 or 98%, we find the value of \alpha=0.02 and \alpha/2 =0.01 using tools like Excel or a calculator, where the Excel command would be: "=-T.INV(0.01,22)". This yields t_{\alpha/2}=2.51

Having all components ready, we can substitute into formula (1):

172-2.51\frac{16}{\sqrt{23}}=163.626    

172+2.51\frac{16}{\sqrt{23}}=180.374

Thus, for this case, the 98% confidence interval will be (163.626;180.374)    

3 0
14 days ago
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