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Marat540
14 days ago
12

A coordinate grid with 2 lines. The first line is labeled y equals negative StartFraction 7 over 4 EndFraction x plus StartFract

ion 5 over 2 EndFraction and passes through the (0, 2.5) and (2.2, negative 1.4). The second line is labeled y equals StartFraction 3 over 4 EndFraction x minus 3 and passes through (0, negative 3, 0.14) and (2.2, negative 1.4) Which is the best approximate solution of the system of linear equations y = 1.5x – 1 and y = 1? (0.33, 1) (1.33, 1) (1.83, 1) (2.33, 1)
Mathematics
2 answers:
AnnZ [3.8K]14 days ago
7 0

Answer:

Question 1: (2.2, -1.4)

Question 2: (1.33, 1)

Detailed solution:

The equations corresponding to the provided lines are:

y=-\frac{7}{4}x+\frac{5}{2}-----(1)

This line crosses through points (0, 2.5) and (2.2, -1.4).

y=\frac{3}{4}x-3------(2)

This line passes through points (0, -3) and (2.2, -1.4).

The objective is to determine the common coordinate point for both lines, i.e., solve the equations simultaneously.

From equations (1) and (2),

-\frac{7}{4}x+\frac{5}{2}=\frac{3}{4}x-3

x(\frac{7}{4}+\frac{3}{4})=\frac{5}{2}+3

\frac{10}{4}x=\frac{11}{2}

Simplifying gives:

x = \frac{11}{2\times 2.5}

which is x = 2.2

Substituting x into equation (2),

y=\frac{3}{4}\times (2.2)-3

y = -1.4

Hence, the solution to these equations is (2.2, -1.4).

Question 2.

The given system is y = 1.5x - 1 and y = 1.

Setting y equal,

1 = 1.5x - 1

Add 1 to both sides:

1.5x = 2

Divide both sides by 1.5:

x = \frac{2}{1.5}=1.33

Therefore, the solution to the system is (1.33, 1).

AnnZ [3.8K]14 days ago
5 0

Answer:

1) (2.2, -1.4)

2) (1.33, 1)

Detailed solution:

Question 1)

We are provided with two linear equations representing lines, and we need to find the intersection point that solves the system.

The lines given are:

Line 1 equation:

y=\frac{-7}{4}x+\frac{5}{2}

This line passes through points (0, 2.5) and (2.2, -1.4).

Line 2 equation:

y=\frac{3}{4}x-3

The second line goes through (0, -3) and (2.2, -1.4).

According to the graph and data, the solution to the system is the coordinate where both lines intersect.

The solution to a system of linear equations is the coordinate pair common to both lines, i.e., the intersection point.

Here, both lines share the point (2.2, -1.4), indicating it is their intersection and the solution.

Therefore, the solution for question 1 is (2.2, -1.4).

Question 2)

The equations given are:

y = 1.5x - 1               Equation 1

y = 1                           Equation 2

The method of substitution can be used to find the solution.

Replacing y from Equation 2 into Equation 1 gives:

1 = 1.5x - 1

Add 1 to both sides:

2 = 1.5x

Dividing both sides by 1.5 yields:

x = 2/1.5

x = 1.33

y = 1

Thus, the solution of the system is (1.33, 1).

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Answer: You would need 40 bushels of seed to plant 30 acres of wheat.

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5 days ago
Suppose the time interval between two consecutive defective light bulbs from a production line has a uniform distribution over a
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Step-by-step explanation:

A uniform probability situation occurs when all outcomes have an equal chance of happening.

In this context, we identify a lower and upper limit for the distribution known as 'a' and 'b', respectively.

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M = \frac{a+b}{2}

The standard deviation of the uniform distribution can be calculated as:

S = \sqrt{\frac{(b-a)^{2}}{12}}

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M = \frac{a+b}{2} = \frac{0 + 90}{2} = 45

The mean of the time interval is 45 minutes.

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P(10 \leq X \leq 35) = \frac{35-10}{90-0} = 0.2778

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The standard deviation of the time interval is 25.98 minutes.

d) What is the probability that the time interval between two consecutive defective light bulbs will be less than 10 minutes?

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7 0
9 days ago
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