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Rashid
1 month ago
8

2 Tables. A 2-column table with 4 rows is titled Table 1. Column 1 has entries 2, 4, 6, 8. Column 2 has entries 3, 6, 9, 12. A 2

-column table with 4 rows is titled Table 2. Column 1 has entries 5, 10, 15, 20. Column 2 has entries 6, 12, 18, 24.
Compare the ratios from the tables.
2:3 is 5:6
10:12 is 6:9
The ratios in Table 1 are the ratios in Table 2.

Mathematics
1 answer:
tester [12.3K]1 month ago
6 0

Response:

2:3 is

✔ lesser than

5:6

10:12 is

✔ greater than

6:9

The ratios shown in Table 1 are

✔ smaller than

those in Table 2

Step-by-step explanation:

You might be interested in
Diego's club earns money for charity when members of the club perform community service after school,
babunello [11817]

Answer: Indeed, because the input value ranges from 0 to 12.

Step-by-step explanation:

To address this query, we first need to formulate a function that reflects the situation.

Every student engaging in community service earns the club $5

E(s) = 5 s

Where:

  • E= total earnings
  • n = number of students participating in community services (input value)

Indeed, since the input value n indicates how many students from the club engage in community service, and with the total number of students being 12, the input can indeed vary between 0 and 12.

6 0
3 months ago
Find the perimeter of a quadrilateral with vertices at C (−2, 1), D (2, 4), E (5, 0), and F (1, −3). Round your answer to the ne
tester [12383]

Answer: 20 units

Step-by-step explanation:

The formula for calculating the distance between two coordinates P(a,b) and Q(c,d) is as follows:-

PQ=\sqrt{(d-b)^2+(c-a)^2}

Initially provided: The coordinates of the quadrilateral's vertices are C (−2, 1), D (2, 4), E (5, 0), and F (1, −3).

The distance between vertices C (−2, 1) and D (2, 4) is as follows:-

CD=\sqrt{(4-1)^2+(2-(-2))^2}\\\\\Rightarrow\ CD=\sqrt{(3)^2+(4)^2}\\\\\Rightarrow\ CD=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ CD=5\text{ units}

Distance between points D (2, 4) and E (5, 0) is calculated as:-

DE=\sqrt{(4-0)^2+(2-5)^2}\\\\\Rightarrow\ DE=\sqrt{(4)^2+(-3)^2}\\\\\Rightarrow\ DE=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ DE=5\text{ units}

Distance between coordinates E (5, 0) and F (1, −3) is given by:-

EF=\sqrt{(-3-0)^2+(1-5)^2}\\\\\Rightarrow\ EF=\sqrt{(-3)^2+(-4)^2}\\\\\Rightarrow\ EF=\sqrt{9+16}=\sqrt{25}\\\\\Rightarrow\ EF=5\text{ units}

Distance from C (−2, 1) to F (1, −3) is as follows:-

FC=\sqrt{(-3-1))^2+(1-(-2))^2}\\\\\Rightarrow\ FC=\sqrt{(-4)^2+(3)^2}\\\\\Rightarrow\ FC=\sqrt{16+9}=\sqrt{25}\\\\\Rightarrow\ FC=5\text{ units}

The total perimeter of the quadrilateral is calculated as = CD + DE + EF + FC

=5+5+5+5=20\text{ units}

3 0
2 months ago
Read 2 more answers
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