Answer:3.87*10^-4
Explanation:
To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.
From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.
Solving gives frequency F=0.87*10^20 Hz.
Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.
Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).
This energy is then converted from joules to MeV.
Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding
3.87*10^-4 u.
Answer:
Explanation:
Transformation of Energy
Also known as energy conversion, this refers to the process in which energy shifts from one type to another. In this context, three energy forms are involved. When the object is stationary at the ramp's peak, it possesses gravitational potential energy, calculated as
As the object descends the frictionless ramp, it converts all its potential energy into kinetic energy, represented as
Thus,
Ultimately, when the object encounters a rough surface, all energy converts to thermal energy. The work performed by the friction force corresponds to the alteration in kinetic energy, as all velocity is lost in this process:
Given the kinetic energy equals the initial potential energy:
The negative sign indicates that the work acted against the direction of movement, meaning the force and displacement are 180° apart.
This outcome is independent of the distance D needed to halt the block or the kinetic friction coefficient.
Answer:
4.05 m/s
Explanation:
We will express the varying velocities as vectors.
Newton moves northward at 3.90 m/s from Daniel's stationary position.
V_n = 3.9 j
Assuming Pauli runs relative to Daniel at velocity X.
The relative velocity of Newton as seen by Pauli will be
3.9 j - X
Given that
the relative velocity of Newton with respect to moving Pauli = 1.1 i (1.1 towards the east).
Thus,
3.9 j - X = 1.1 i
X = -1.1 i + 3.9 j.
Magnitude of X
X² = 1.1² + 3.9²
X = 4.05 m/s
Therefore, Pauli runs relative to Daniel at 4.05 m/s.
The direction will be west of north at an angle θ,
Tan θ = 1.1 / 3.9
Speed is defined as distance over time. Hence, to determine the distance, we use d = V * t. Plugging in the values yields d = (72 Km / h) * (1h / 3600s) * (4.0 s) = 0.08Km. Thus, during this distracted period, a distance of 0.08Km was covered.
Given
m1(mass of red bumper): 225 Kg
m2 (mass of blue bumper): 180 Kg
m3(mass of green bumper): 150 Kg
v1 (velocity of red bumper): 3.0 m/s
v2 (final velocity of the combined bumpers):?
The principle of momentum conservation indicates that the momentum before impacts equals the momentum after impacts. This can be represented mathematically as:
Pa= Pb
Pa symbolizes the momentum prior to collision and Pb refers to momentum after collision.
Applying this principle to the aforementioned scenario results in:
Momentum pre-collision= momentum post-collision.
Momentum pre-collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s
Momentum post-collision = (m1+m2+m3) x v2 =(225+180+150)x v2
=555v2
We now know that Momentum pre-collision equals momentum post-collision.
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1215 = 555 v2
v2 = 2.188 m/s
Consequently, the final velocity of the combined bumper cars is 2.188 m/s
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