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Diano4ka-milaya
8 days ago
10

The PVT behavior of a certain gas is described by the equation of state: P(V − b) = RT where b is a constant. If in addition CV

is constant, show that: (a) U is a function of T only. (b) γ = const. (c) For a mechanically reversible process, P(V − b)γ = const.

Physics
1 answer:
Softa [2.9K]8 days ago
6 0
For thorough details and necessary calculations, please refer to the attachment.
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A cart moves along a track at a velocity of 3.5 cm/s. when a force is applied to the cart, its velocity increases to 8.2 cm/s. i
inna [2995]
In physics, acceleration describes how an object's velocity changes over time. Whenever the speed of an object shifts, it's considered to be accelerating. To calculate acceleration here:

acceleration = (8.2 - 3.5) / 1.5 = 3.1 m/s²

I trust this answers your question.
5 0
1 month ago
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Suppose that 8 turns of a wire are wrapped around a pipe with a length of 60 inches and a circumference of 4​ inches, so that th
inna [2995]

Answer:

The wire length is 32 inches.

Explanation:

According to the question,

The pipe's length = 60 inches

The pipe's circumference = 4 inches

Now,

The wire wraps around the pipe for 8 complete turns.

Now, with 2πr = 4, we find that

r = 2/π

Thus,

The radius, r = 2/π

The wire's length can be calculated as,

Length = Number of turns x Circumference of the pipe

So, length of wire = 8 x 4 = 32 inches.

Consequently, the wire length is 32 inches.

7 0
1 month ago
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A ball rolls up a slope. At the end of three seconds its velocity is 20 cm/s; at the end of eight seconds its velocity is 0. Wha
serg [3485]

Answer:

a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

Explanation:

Data provided

initial velocity v₀=20 cm/s at time t=3s

final velocity vf=0 at time t=8 s

Required

Average Acceleration for the interval from 3s to 8s

Solution

Acceleration can be defined as the first derivative of velocity concerning time

a_{acceleriation} =\frac{dv_{velocity}}{dt_{time}}\\a_{acceleriation} =\frac{v_{f}-v_{o} }{dt}\\ a_{acceleriation} =\frac{0-20cm/s }{8s-3s}\\ a_{acceleriation}=-4cm/s^{2}\\ or\\ a_{acceleriation}=-0.04m/s^{2}

8 0
16 days ago
a fixed mass of a n ideal gas is heated from 50 to 80C at a constant pressure at 1 atm and again at a constant pressure of 3 atm
inna [2995]

Answer:

The required energy remains identical in both scenarios since the specific heat capacity (Cp) does not change with varying pressure.

Explanation:

Given;

initial temperature, t₁ = 50 °C

final temperature, t₂ = 80 °C

Temperature change, ΔT = 80 °C - 50 °C = 30 °C

Pressure for scenario one = 1 atm

Pressure for scenario two = 3 atm

The energy needed in both scenarios is expressed as;

Q = M*C_p*\delta T

Where;

Cp denotes specific heat capacity, which only varies with temperature and remains unaffected by pressure.

Hence, the energy required remains the same for both scenarios since specific heat capacity (Cp) is pressure-independent.

8 0
1 month ago
A person drops a stone down a well and hears the echo 8.9 s later. if it takes 0.9 s for the echo to travel up the well, approxi
Sav [3056]
The total duration from the stone's drop to the echo being heard is 8.9 seconds. The sound takes 0.9 seconds to reach the listener, meaning it takes the stone 8 seconds to descend to the well's bottom. Using gravitational acceleration, the well's depth calculates to be approximately 313.6 meters.
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