Potential energy matter has a result of its ____ or ____.

Response:

The ball remained airborne for 3.896 seconds

Explanation:

Given that

g = 9.8 m/s², representing gravitational acceleration,

If the angle of launch is 45°, the horizontal range will be maximized.

Both horizontal and vertical launch velocities are equal, each equating to

v_h  =  v cos θ

v_h  =  27 × cos 45°

         = 19.09 m/s.

The duration to reach maximum height is half of the flight time.

v = u + at   ∵ v = 0 (at maximum height)

19.09 - 9.8 t₁ = 0

t₁ = 1.948 s

The total time in the air equals twice the time to reach maximum height

2 t₁ = 3.896 s

The horizontal distance covered is

D = v × t

D = 3.896×19.09

   = 74.375 m

The ball was in the air for 3.896 seconds

Mike will get an electric shock. Explanation: The human body acts as a conductor of electricity. When lightning strikes the rod, it acquires a negative charge and immediately discharges this charge when contacting the ground through conductive materials. As a result, Mike is likely to endure a significant electric shock as the negative charge travels through his body to the other rod and into the ground, potentially leading to numbness or even loss of consciousness.

Answer:3.87*10^-4

Explanation:

To determine the mass reduction, delta mass Xe, of the xenon nucleus due to its decay, we first use the provided wavelength of the gamma radiation to calculate its frequency via c = freq*wavelength.

From C=f*lambda we set up: 3*10^8=f*3.44*10^-12.

Solving gives frequency F=0.87*10^20 Hz.

Next, we calculate the emitted energy using the equation E=hf, which translates to E=f*Planck's constant.

Thus, E=0.87*10^20*6.62*10^-34, resulting in E=575.94*10^(-16).

This energy is then converted from joules to MeV.

Utilizing the formula E=mc^2, with c^2 = 931.5 MeV/u, enables us to find the reduction in mass, yielding

3.87*10^-4 u.

Answer:

3x864/y488bjehdksuwiieirjr

Answer:

Explanation:

An image of the bond resulting from the search is attached.

Consider the force directed towards thymine as negative.

For the O-H-N combination:

The resulting force from this combination is:

In the case of the N-H-N combination:

The total force acting from this combination is:

The force that thymine applies on adenine is:

When rounded to three significant figures, the net force is

b)

The negative value indicates that the force is attractive, as it is aimed towards thymi.

c)

The force acting on the electron due to the proton is:

Since the electron and proton carry opposite charges, the force on the electron points towards the proton.

d)

The ratio of the above forces is:

Therefore, the bonding strength of the electron in the hydrogen atom is 9.3 times greater than the bonding force between adenine and thymine molecules.