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Gelneren
5 days ago
9

Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is

then loaded with 1,000 kg of bricks. Which of the following would be the new gravitational force between the two trucks?
Physics
1 answer:
Yuliya22 [3.2K]5 days ago
8 0
The new gravitational force would be calculated as follows: Consider the general formula for the gravitational force between two masses m1 and m2 that are separated by a distance "d". For the two trucks weighing 2,000 kg each, the gravitational force is initially 3.00 × 10-5 N. When one truck is loaded with an additional 1,000 kg of bricks, we need to determine the new gravitational force (x). We find this by dividing the last equation by the original to eliminate common factors (G, d^2).
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The concrete post (Ec = 3.6 × 106 psi and αc = 5.5 × 10-6/°F) is reinforced with six steel bars, each of 78-in. diameter (Es = 2
Maru [3237]

Answer:

the normal stress caused by the concrete post \sigma_c = 67.26 psi

the normal stress caused by the steel \sigma_s = - 1795.84 psi

Explanation:

Given that:

Modulus of elasticity for the concrete post E_c = 3.6 *10^6 psi

Thermal coefficient for concrete post  \alpha _c = 5.5 *10^{-6}/^0F

Modulus of elasticity for the steel bar E_s = 29*10^6psi

Thermal coefficient of steel bar \alpha _2 = 6.5*10^{-6}/^0F

Change in temperature ΔT = 80°F

Diameter of the steel rod = 7/8-in

Area of the steel rod A_s = 6(\frac{ \pi}{4} )(d_s)^2

= 6(\frac{ \pi}{4} )(\frac{7}{8} )^2

= 3.61 in²

Area of concrete parts A_c = (10)(10) - A_s

= (100 - 3.61) in²

= 96.39 in²

The total strain developed in the concrete post can be expressed as:

= [\frac{1}{E_cA_c}+\frac{1}{E_sA_s}]P=(\alpha_s-\alpha_c)(\delta T)

= [\frac{1}{(3.6*10^6)(96.39)}+\frac{1}{(29*10^6)(3.61)}]P=(6.5*10^{-6}-5.5*10^{-6})(80)

= [(2.88*10^{-9}) +(9.55*10^{-9}]P = 8.0*10^{-5}

= 1.234*10^{-8}P = 8.0*10^{-5}

P = \frac {8.0*10^{-5}}{1.234*10^{-8}}

P = 6482.98 lb

Since, the normal stress in concrete is induced from the temperature increase; we derive the expression:

\sigma_c =\frac{P}{A_c}

\sigma_c = \frac{6482.98}{96.39}

\sigma_c = 67.26 psi

Thus, the normal stress caused by the concrete post \sigma_c = 67.26 psi

Also, the normal stress in the steel bars induced due to the temperature change is represented as follows:

\sigma_s = \frac{-P}{A_s}

\sigma_s =\frac{-6482.98}{3.61}

\sigma_s = - 1795.84 psi

Thus, the normal stress caused by the steel \sigma_s = - 1795.84 psi

6 0
11 days ago
A water-skier with weight Fg = mg moves to the right with acceleration a. A horizontal tension force T is exerted on the skier b
Maru [3237]

Answer:

The accurate equations are T-fg=ma and L-fg=0.

Options (A) and (C) are valid.

Explanation:

Given that:

Weight Fg = mg

Acceleration = a

Tension = T

Drag force = Fa

Vertical force = L

We are required to determine the correct relationships

Using the equilibrium equations

Horizontally,

The acceleration is a

T-Fd=ma...(I)

Vertically,

No acceleration occurs

w=L

mg-L=0

Substituting the value of mg

L-fg=0....(II)

Thus, the correct relationships are T-fg=ma and L-fg=0.

Options (A) and (C) are correct.

3 0
1 month ago
The thrust of a certain boat’s engine generates a power of 10kW as the boat moves at constant speed 10ms through the water of a
ValentinkaMS [3319]

Answer:

The power increase is 4400 W.

Explanation:

Given data,

Power = 10 kW

Initial speed = 10 m/s

New speed = 12 m/s

The relevant equation is:

F=kv

It's known that,

The expression for power is,

P=Fv

Substituting the value of F into the formula gives

P=(kv)v

P=kv^2

P\propto v^2

Now we must determine the new power

By applying the power formula

\dfrac{P}{P'}=\dfrac{v^2}{v'^2}

Insert the value into the equation

\dfrac{10}{P'}=(\dfrac{10}{12})^2

P'=(\dfrac{12}{10})^2\times10

P'=14.4\ kW

Next, we calculate the change in power

Using the formula for power change

\Delta P=P'-P

Insert values into the equation

\Delta P=14.4-10

\Delta P=4.4\ kW

\Delta P=4.4\times1000

\Delta P=4400\ W

Thus, the change in power amounts to 4400 W.

6 0
1 month ago
Which table correctly identifies the abbreviation for SI units of length mass volume and temperature
Ostrovityanka [3021]

Response: b

Clarification:

Temperature: kelvin

Mass: kilogram

Length: meter

Volume: cubic meter

(Apex learning test)

8 0
5 days ago
A mechanical high-speed bat is flying along a path perpendicular to a wall. it emits a sound with a frequency f0 . the night is
inna [2965]
1. f1 = Vs + Vbat Vs fO
2. f1 = Vs Vs - Vbat fO
3. f1 = Vs Vs + Vbat fO
4. f1 = Vs + Vbat Vs - Vbat fO
5. f1 = 2Vs Vs - Vbat fO
6. f1 = Vs - Vbat Vs fO
7. f1 = Vs - Vbat Vs + Vbat fO
8. f1 = fO
9. f1 = 2Vs Vs + Vbat fO

The frequency that is detected is
f= (V+Vr) × fO/ (V + Vs)
The speed of sound is V = Vs
The speed of the receiver is Vr = O
For the speed of the source
Vs = -Vbat, indicating that the bat approaches the wall
Therefore, the correct formula is
f1 = (Vs / (Vs -Vbat)) × fO.
4 0
1 month ago
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