Set t = 0 to find the initial height
Response:
a. 0.76
b. 0.23
c. 0.5
d. p(B/A) signifies the likelihood that a student with a visa card also possesses a MasterCard.
p(A/B) indicates the probability that a student with a MasterCard also has a visa card.
e. 0.35
f. 0.31
Detailed explanation:
a. p(AUBUC) = P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) + P(AnBnC)
= 0.6 + 0.4 + 0.2 - 0.3 - 0.11 - 0.1 + 0.07 = 0.76
b. P(AnBnC') = P(AnB) - P(AnBnC)
= 0.3 - 0.07 = 0.23
c. P(B/A) = P(AnB)/P(A)
= 0.3/0.6 = 0.5
e. P((AnB)/C) = P((AnB)nC)/P(C)
= P(AnBnC)/P(C)
= 0.07/0.2 = 0.35
f. P((AUB)/C) = P((AUB)nC)/P(C)
= (P(AnC) U P(BnC))/P(C)
= (0.11 + 0.1)/0.2
= 0.21/0.2 = 0.31
The diagonal measures 20.68 ft; the shorter base is 17.21 ft. To understand this, we recognize that with base angles summing to 140°, each angle is 70°, given the isosceles trapezoid's properties. We can apply the Law of Cosines to find the diagonal's length, denoted as d. The length of the diagonal determines to be d = 20.68 ft. Determining the shorter base is somewhat more complex. By drawing an altitude from the upper vertices to the base, which measures 22 ft, we create two similar smaller right triangles requiring us to find the height and base measures related to each of the 70-degree angles and the hypotenuse of 7. By working through the calculations for height and base from one triangle, we subsequently find that 22 minus twice the base measure gets us to the shorter base's measure, arriving at x = 17.21 ft.
