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slega
8 days ago
15

Select the points that are solutions to the system of inequalities. Select all that apply A. (-12, 0) B. (1, 2) C. (0, 0) D. (-1

0, 1)

Mathematics
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Mia paints interior walls at a rate of 12 m^2/h. At what rate does she paint in cm^2/min?
Inessa [12570]
12 m^2/h to cm^2/min

12 m^2/h × 1 h/60 min = 0.2 m^2/min

0.2 m^2/min × 10000 cm^2/1 m^2 = 2000 cm^2/min

2000 cm^2/min
6 0
2 months ago
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Bart used place value and the distributive property to rewrite the expression 6(412). His work is shown below. 6(412) = 6(400 +
PIT_PIT [12445]

Bart needs to;

Calculate 6(400), 6(10), and 6(2) ⇒ 2nd

Calculate each addend multiplied by 6 ⇒ 4th

Determine the total of (2400 + 60 + 12) ⇒ 5th

Step-by-step breakdown:

We'll review the distributive property

  • a(b + c) = ab + ac
  • a(b + c + d) = ab + ac + ad

Bart applied place value along with the distributive property to express the

calculation 6(412)

His calculation can be represented as 6(412) = 6(400 + 10 + 2)

We must find out what Bart needs to do to compute the product

∵ 6(412) = 6(400 + 10 + 2)

- Multiply every component inside the brackets by 6 on the right side

∴ 6(400 + 10 + 2) = (6)(400) + (6)(10) + 6(2)

∴ 6(400 + 10 + 2) = 2400 + 60 + 12

∴ He should multiply each addend by 6, then calculate the total of

  (2400 + 60 + 12)

Bart needs to;

Calculate 6(400), 6(10), and 6(2)

Multiply each addend by 6

Compute the total of (2400 + 60 + 12)

Learn more:

You can find additional information regarding place value at

5 0
1 month ago
Read 2 more answers
Decimal 0.003 is 1/10 of
zzz [12365]
To determine the result of multiplying 0.003 by 10, you will simply multiply as such. A straightforward method is to shift the decimal point one place to the right (it would shift two places for multiplying by 100, and three for 1000, etc.). The same rule applies when dividing; just ensure to move left instead.

Hence, the result is 0.03.

<span>I hope that was helpful!!!</span>
6 0
3 months ago
Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a
Inessa [12570]

Answer:

y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)

6 0
3 months ago
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The law of cosines is a^2+b^2-2abcosC=c^2. Find the value of 2abcosC.
zzz [12365]
2ab x cos(C) = 7 since

a^2 + b^2 - 2ab x cos(C) = c^2
2ab x cos(C) = a^2 + b^2 - c^2
2ab x cos(C) = 2^2 + 2^2 - 1^2
2ab x cos(C) = 7
4 0
2 months ago
Read 2 more answers
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