Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40' Building Als 120 feet away, and b

Question

12 days ago

5

Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40' Building Als 120 feet away, and b

uilding B is 60 feet away which building is taller and by approximately how many feet?
Building A It is around 100 69 feet taller than building B
Building A it is around 50 34 feet taller than building B
O Building B, it is around 100.69 feet taller than building A
Building B, it is around 50.34 feet taller than building A

Mathematics

2 answers:

tester [8.8K] · Answer 1 · 2026-03-16T11:03:32+03:00

A. Building A, which is approximately 100.69 feet taller than building B. To determine this, since building A sits 120 feet away at an elevation of $40^{0}$ , we use: Tan $40^{0}$ = $\frac{x}{120}$ . Let x represent the height of the building at the horizontal level, resulting in x = Tan $40^{0}$ × 120 = 100.692 feet. For building B, located at the same elevation, apply Tan $40^{0}$ = $\frac{x}{60}$ . Thus, x = Tan $40^{0}$ × 60 = 50.346 feet. Given the same angles of elevation, building A stands around 100.69 feet taller than building B.

zzz [9K] · Answer 2 · 2026-03-16T11:06:34+03:00

zzz [9K]12 days ago

3 0

Building A exceeds Building B in height by 50.34 feet. One should subtract both measurements.