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10 days ago

A real number in between 13 and 14 square root

1 answer:

6 0

<span>Real numbers can be either rational or irrational.
sqrt(13) ≈ 3.60555
sqrt(14) ≈ 3.74166
A simple nearby rational approximation is 3.7 = 37/10.
An example of an irrational number between them is sqrt(27/2).</span>

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Kevin plants a total of 72 flowers in equal rows he plants 6 rows of yellow flowers and 2 rows of red flowers how many flowers a

PIT_PIT [11856]

For the red flowers, there are 18 in each row. For the yellow flowers, there are 6 in each row.

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20 days ago

Ayesha works as a real estate agent. Her annual gross salary is $28,000. From this, she must pay 20% income tax on anything earn

Zina [11921]

Answer:

Step-by-step explanation:

Annual gross salary = $28000

Income tax = 20% applicable to earnings exceeding $15000

Thus, she has a taxable amount of $5000

Rent loan equals $140 monthly = $140 * 12= $1680 per year

Tax deductible annually would be 20% of $5000

20 / 100 * $5000 = $1000

Her total net income annually is equal to

Gross salary per annum - tax - loan =

($28000 - $1000 - $1680) = $25,320

Ayesha's take-home pay annually is $25,320.

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14 days ago

Before the last school year began, it was estimated that the average discretionary personal expenses each school year for a stud

tester [11824]

Answer:

M=2,179.29

The average exceeds the estimate

Her expenses would need to be $1,625.00

Step-by-step explanation:

1.) What is the mean of her friends' personal expenses?

The mean is defined as the average expense value, calculated as follows:

$M=\frac{2,800+1,990+2,005+2,400+1,860+2,200+2,000}{7}\\M=2,179.29$

2.) Is the average higher or lower than the estimate?

Given the estimate of $2,110, the average is indeed higher than this estimate.

3.)What amount of personal expenses would Ashley need to maintain a combined average of $2,110 with her friends' amounts for that school year?

$M= 2,110=\frac{7*2,179.29+x}{8} \\x=2,110*8 - 15,255\\x=1,625$

Her needed amount of expenses would be $1,625.00.

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15 days ago

Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC

Svet_ta [12210]

We are given the triangle

△ABC, with m∠A=60° and m∠C=45°, and AB=8.

To start, we will calculate all angles and sides.

Finding angle B:

The total of all angles in a triangle equals 180.

m∠A + m∠B + m∠C = 180.

Substituting the known values,

60° + m∠B + 45° = 180.

This gives us m∠B = 75°.

Calculating BC:

Using the law of sines,

$\frac{AB}{sin(C)}=\frac{BC}{sin(A)}$

We can substitute in the values.

$\frac{8}{sin(45)}=\frac{BC}{sin(60)}$

$BC=\frac{8}{sin(45)} \times sin(60)$

$BC=9.798$

Finding AC:

$\frac{AB}{sin(C)}=\frac{AC}{sin(B)}$

Now we'll input the values.

$\frac{8}{sin(45)}=\frac{AC}{sin(75)}$

$AC=\frac{8}{sin(45)} \times sin(75)$

$AC=10.928$

Calculating Perimeter:

$p=AB+BC+AC$

We substitute values here as well.

$p=10.928+8+9.798$

$p=28.726$

Calculating Area:

Using the area formula,

$A=\frac{1}{2}AB \times AC \times sin(A)$

we can then insert values.

$A=\frac{1}{2}8 \times 10.928 \times sin(60)$

$A=37.85570$ ...............Answer

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1 month ago

Read 2 more answers

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1 month ago