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Blababa
2 months ago
10

Based on FAA estimates the average age of the fleets of the 10 largest U.S. commercial passenger carriers is 13.4 years with a s

tandard deviation of 1.7 years. Suppose that 40 airplanes were randomly selected from the fleets of these 10 carriers and were inspected for cracks in these airplanes that are considered too large for flying. What is the probability that the average age of these 40 airplanes is at least 14 years old? Round your answer to 4 decimal places. Remember to round your z-value to two decimal places.
Mathematics
1 answer:
Leona [12.6K]2 months ago
6 0
The result is 0.0129. The data to consider includes the mean and standard deviation for the random variable associated with the fleets' ages. Calculating the Z-score for x = 14 and using the standard normal distribution table yields the probability that the average age of the 40 sampled airplanes is at least 14 years, rounded to four decimal places as 0.0129.
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A sequence is defined by mc024-1.jpg, and mc024-2.jpg. What is the seventh term?
AnnZ [12381]
Given data:
a₃ = 9/16
aₓ = -3/4 · aₓ₋₁
Here, x represents the number of terms ('x' can also be referred to as 'n')
To determine the 7th term (a₇):

We know that aₓ = -3/4 · aₓ₋₁
Thus,[ [TAG_10]]a₃ = -3/4 · a₃₋₁
a₃ = -3/4 · a₂
9/16 = -3/4 · a₂
a₂ = 9/16 × -4/3
a₂ = -36/48
a₂ = -3/4

Next,[ [TAG_20]]aₓ = -3/4 · aₓ₋₁
a₄ = -3/4 · a₄₋₁
a₄ = -3/4 · a₃
a₄ = -3/4 · 9/16
a₄ = -27/64
a₄ = -27/64

For a₅,[ [TAG_30]]aₓ = -3/4 · aₓ₋₁
a₅ = -3/4 · a₅₋₁
a₅ = -3/4 · a₄
a₅ = -3/4 × -27/64
a₅ = 81/256

For a₆,[ [TAG_39]]aₓ = -3/4 · aₓ₋₁
a₆ = -3/4 · a₆₋₁
a₆ = -3/4 · a₅
a₆ = -3/4 × 81/256
a₆ = -243/1024

Finally, for a₇,[ [TAG_48]]aₓ = -3/4 · aₓ₋₁
a₇ = -3/4 · a₇₋₁
a₇ = -3/4 · a₆
a₇ = -3/4 × -243/1024
a₇ = 729/4096
3 0
1 month ago
Read 2 more answers
estimate the total weight of two boxes that weigh 9.4 lb and 62.6 lb using rounding and compatible numbers. which estimate is cl
babunello [11817]
<span><span>1.      </span>We have two boxes with weights:
=> 9.4 lb and 62.6 lb.
To find a rough estimate of their total weight, we will round and use compatible numbers.
For 9.4 lbs, rounding gives us 9 lbs
And for 62.6 lbs, it rounds to 63 lbs
=> Adding these two rounded numbers yields:
=> 9 + 63
=> 72, the estimated total is 72.
Let’s verify if this is close to the actual weight
=> 9.4 + 62.6
=> 72</span>



5 0
2 months ago
1.62 was multiplied by a power of ten to get 16.2. What power of ten was it multiplied by?
zzz [12365]
10 raised to the first power,
so indeed.
8 0
2 months ago
Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10
lawyer [12517]

Response:

0011100000

1010010001

0111001110

Detailed explanation:

Since the question is incomplete, here is the full question.

Assume the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Represent each of these sets using bit strings, where the ith bit indicates 1 if the element i is part of the set, and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

Thus, we need to convert a), b), and c) into bit strings.

To begin with, the number of items in the universal set determines the number of bits in the bit string.

Next, a 1 denotes the presence of an element both in the universal set and in the subset.

A 0 indicates that an element is absent from the subset but present in the universal set.

Therefore, we obtain:

a) Subset {3,4,5} = 0011100000  (As it contains 3 ones, it shows that only 3,4,5 are included in both the universal and the subset.

In the same way,

b) Subset {1, 3, 6, 10} = 1010010001

c) Subset {2, 3, 4, 7, 8, 9} = 0111001110

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A concert promoter sells tickets and has a​ marginal-profit function given​ below, where Upper P prime (x )is in dollars per tic
Inessa [12570]
09
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