Response:
A. {(–4, 3), (–2, 7), (–1, 0), (4, –3), (11, –7)}
Detailed explanation:
Having just taken the quiz, it's worth noting that you can interchange the coordinates to observe those of the inverse function. Instances of identical x values indicate that it fails the line test, thus disqualifying it as a function with an inverse.
a) P(identified as explosive) equals P(actual explosive & identified as explosive) + P(not explosive & identified as explosive) = (10/(4*10^6))*0.95+(1-10/(4*10^6))*0.005 = 0.005002363. Thus, the probability that it actually contains explosives given that it's identified as containing explosives is (10/(4*10^6))*0.95/0.005002363 = 0.000475. b) Let the probability of correctly identifying a bag without explosives be a. Therefore, a = 0.99999763, approximately 99.999763%. c) No, even if this becomes 1, the true proportion of explosives will always be below half of the total detected.
Given the three integers are
, we arrive at

We can merge the fractions on the left side:


Response:
The correct choice is option C
The proportion of green marbles to red marbles is 3: 1
Step-by-step breakdown:
According to the problem statement:
A bag holds 44 marbles, comprising both red and green ones.
⇒Total marbles = 44
If it includes 11 red marbles.
Then;
Green marbles = Total marbles - red marbles.
By substituting the values provided,
Green marbles = 44 - 11 = 33
We are tasked with determining the ratio of green marbles to red marbles.

Consequently, the ratio of green to red marbles is 3: 1