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Ivenika
2 months ago
6

Suppose that the universal set is U={1,2,3,4,5,6,7,8,9,10}. Express each of the following subsets with bit strings (of length 10

) where the ith bit (from left to right) is 1 if i is in the subset and zero otherwise.
Mathematics
1 answer:
lawyer [12.5K]2 months ago
5 0

Response:

0011100000

1010010001

0111001110

Detailed explanation:

Since the question is incomplete, here is the full question.

Assume the universal set is U = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Represent each of these sets using bit strings, where the ith bit indicates 1 if the element i is part of the set, and 0 otherwise.

a) {3, 4, 5}

b) {1, 3, 6, 10}

c) {2, 3, 4, 7, 8, 9}.

Thus, we need to convert a), b), and c) into bit strings.

To begin with, the number of items in the universal set determines the number of bits in the bit string.

Next, a 1 denotes the presence of an element both in the universal set and in the subset.

A 0 indicates that an element is absent from the subset but present in the universal set.

Therefore, we obtain:

a) Subset {3,4,5} = 0011100000  (As it contains 3 ones, it shows that only 3,4,5 are included in both the universal and the subset.

In the same way,

b) Subset {1, 3, 6, 10} = 1010010001

c) Subset {2, 3, 4, 7, 8, 9} = 0111001110

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To identify values of c that digit 5−3c greater than 80

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2 months ago
A box has 14 camera of which 6 are refurbished and 8 are new. If four of these 14 cameras are selected at random without replace
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Answer:

160/1001, 175/1001

Step-by-step explanation:

i) We calculate:

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₆C₃ methods to select 3 refurbished cameras from a selection of 8

₁₄C₄ methods to select 4 cameras from the total of 14 cameras

The probability formula is:

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ii) For at most one new camera, it means we want either one new camera or none at all. We've calculated the probability of selecting one new camera already. The probability of not selecting any new camera is equivalent to selecting 4 refurbished cameras:

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Therefore, the combined probability is:

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Answer:

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