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Flauer
3 months ago
10

Two ferries travel across a lake 50 miles wide. One ferry goes 5 miles per hour slower than the other. If the slower ferry leave

s 1 hour earlier than the faster, but both arrive at the same time, what is the speed of the slower ferry
Mathematics
1 answer:
Svet_ta [12.7K]3 months ago
5 0

Answer:

Step-by-step explanation:

Let x represent the speed of the first ferry.

Consequently, the second ferry's speed is x-5, as it travels 5 miles per hour slower.

The time taken by the first ferry is calculated as distance divided by speed = \frac{50}{x}

The time taken by the second ferry equals \frac{50}{x-5}.

Since the second ferry departs one hour earlier, the times differ by 1 hour.

\frac{50}{x-5}-\frac{50}{x}=1\\50x-50(x-5)=x(x-5)\\250 = x^2-5x\\x^2-5x-250 =0\\(x-10)(x+5) =0\\x=18.5, -13.5

The speed cannot be negative.

Thus, the speed of the first ferry is determined to be 18.5 mph,

and for the second, slower ferry, it equals 13.5 mph.

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