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tatiyna
5 days ago
14

In Melanie's Styling Salon, the time to complete a simple haircut is normally distributed with a mean of 25 minutes and a standa

rd deviation of 4 minutes. For a simple haircut, the middle 90 percent of the customers will require:a) between 20.0 and 30.0 minutes.b) between 18.4 and 31.6 minutes.c) between 17.2 and 32.8 minutes.d) between 19.9 and 30.1 minutes.
Mathematics
1 answer:
zzz [9K]5 days ago
3 0

Answer:

b) falls between 18.4 and 31.6 minutes.

Step-by-step explanation:

Problems involving normally distributed samples can be tackled using the z-score formula.

In any set with a mean \mu and standard deviation \sigma, the z-score for a measurement X is calculated as follows:

Z = \frac{X - \mu}{\sigma}

The Z-score indicates how many standard deviations an observation diverges from the mean. After determining the Z-score, consulting the z-score table provides the associated p-value. This p-value represents the likelihood of observing a measure less than X, i.e., the percentile of X. Subtracting the p-value from 1 yields the probability of observing a measure greater than X.

In this question, we find that:

\mu = 25, \sigma = 4

To cover the Middle 90%

The lower limit is determined as the value of X when Z corresponds to a p-value of 0.5 - 0.9/2 = 0.05.

The upper limit corresponds to the value of X when Z has a p-value of 0.5 + 0.9/2 = 0.95.

Lower limit:

X when Z = -1.645Z = \frac{X - \mu}{\sigma}

-1.645 = \frac{X - 25}{4}

X - 25 = -1.645*4

X = 18.42

Upper limit:

X when Z = 1.645

1.645 = \frac{X - 25}{4}

X - 25 = 1.645*4

X = 31.58

Thus, the correct assessment is:

b) between 18.4 and 31.6 minutes.

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A bag holds 12 red marbles, 11 green marbles, 17 blue marbles, and 5 yellow marbles. What is the probability that you will not c
Zina [9171]

¡Hola! Bienvenido a!

Vamos a sumar cuántas canicas tenemos en total.

12+11+17+5=45

Queremos hallar la probabilidad de elegir una canica que no sea azul. Observemos cuántas canicas no son azules.

12+11+5=28

Tendremos esta probabilidad sobre 48.

28/48

Al simplificar, obtenemos 7/12 o alrededor de 58.33%.

¡Espero que esto ayude!

7 0
26 days ago
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A new car is purchased for 17300 dollars. The value of the car depreciates at 9.25% per year. What will the value of the car be,
lawyer [9240]

Answer: 13

I made an error on the question, and it provided the right answer. Thank me later.

4 0
1 month ago
Segment JK has a length of 4.5 units. If segment LM has end points of L (3,1) and M (-1,4), how much longer than segment JK is s
Leona [9271]
Distance formula:
d= \sqrt{ (x_{2}-x_{1}) ^{2}+( y_{2} - y_{1} )^{2}}\\ d= \sqrt{ (3-(-1)) ^{2}+(1 - 4 )^{2}}\\ d= \sqrt{ (4) ^{2}+(-3)^{2}}\\ d=\sqrt{16+9}\\ d=\sqrt{25}\\ d=5

5 units-4.5 units=0.5 units

Segment LM exceeds segment JK by 0.5 units.
4 0
17 days ago
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Stacy wishes to reduce the milk fat content of 5 pints of cream which is 15% fat by combining it with 7 pints of milk which is o
AnnZ [9099]

Answer:

The fat percentage in the blend amounts to 8%.

Step-by-step explanation:

Let

x -----> represent the fat percentage in the mix.

We understand that

The total of milk's volume times its fat percentage, added to cream's volume times its fat ratio, must match the overall mixture's volume times its fat percentage.

Keep in mind that

15% = 15/100 = 0.15

3% = 3/100 = 0.03

therefore

5(0.15)+7(0.03)=(5+7)(x)

Now, solve for x

0.75+0.21=12x

0.96=12x

x=0.08

Convert that into a percentage

0.08*100=8\%

4 0
23 days ago
Lesson 3 homework practice mean absolute deviation
AnnZ [9099]
To calculate the mean absolute deviation of
1,2,3,4,5,6,7
, we start by finding the mean;
 (1+2+3+4+5+6+7) =28/7
                               = 4
. Next, we determine the absolute differences of each data point from the mean (x-μ)
 = -3,-2,-1,0,1,2,3
. The absolute values are 3,2,1,0,1,2,3
. Now we compute the mean of these absolute differences,
3+2+1+0+1+2+3 = 12
                           = 12/7
                           = 1.7143
. Thus, the mean is 4, and the Mean absolute deviation comes out to be 1.7143
4 0
14 days ago
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