Explanation:
The following data has been provided:
Energy of radiation absorbed by the electron in the hydrogen atom = 
As energy is absorbed in the form of a photon, the frequency is calculated accordingly:
E = 
= 
= 
or, = 
It is known that 
= 
According to the De-Broglie equation 
with p = 
So, 
= 
Squaring both sides gives us:
= 
= 
where m = mass of the electron
Therefore,
=
=
J
Since K.E = 
= 
=
Our conclusion is that the kinetic energy gained by the electron in the hydrogen atom is 
.
Response:
9.606 g
Clarification:
Step 1: Write the balanced combustion equation
C₂H₆O(l) + 3 O₂(g) → 2 CO₂(g) + 3 H₂O(g)
Step 2: Determine the moles for 11.27 g of H₂O
The molar mass of H₂O is 18.02 g/mol.
11.27 g × (1 mol/18.02 g) = 0.6254 mol
Step 3: Find the moles of C₂H₆O that produced 0.6254 moles of H₂O
The ratio of C₂H₆O to H₂O is 1:3. Thus, the moles of C₂H₆O are 1/3 × 0.6254 mol = 0.2085 mol
Step 4: Calculate the mass for 0.2085 moles of C₂H₆O
The molar mass of C₂H₆O is 46.07 g/mol.
0.2085 mol × 46.07 g/mol = 9.606 g
Answer:
Calcium's atomic radius is roughly 175 pm.
Explanation:
We know that magnesium has an atomic radius of 150 pm.
The atomic radius of strontium measures 200 pm.
Since calcium's position is between magnesium and strontium in group 2 of the periodic table, its atomic radius should be roughly averaged between magnesium's and strontium's atomic radii because atomic radius is not constant.
Thus;
Calcium's atomic radius is approximately calculated as follows;
The average atomic radius is (200 + 150)/2 = 175 pm.
Answer: The process of heating a crucible to eliminate moisture from a hydrate.
Explanation:
The available choices are:
a. Heating a solvent to aid in the dissolution of a solute.
b. Heating a solid in isolation to remove moisture.
c. Bringing water to a boil for use in a water bath.
d. Heating a crucible to eliminate moisture from a hydrate.
Possible actions that can be done on a hot plate include:
a. Heating a solvent to assist a solute in dissolving.
b. Heating a solid in isolation to dry it.
c. Heating water to boiling for a water bath.
However, it's important to note that using a hot plate for heating a crucible to remove water from a hydrate is not advisable. Silica or ceramic materials are not meant to be heated on a hot plate.
Consequently, the correct procedure is heating a crucible to remove water from a hydrate.
Response:
4.5 m³
Resolution:
The statement indicates the presence of two blocks on a lid of a container with a volume of 9 m³. The lid's weight is equal to that of the two blocks. Thus, there were initially four blocks (or 4 atm pressure) acting on a volume of 9 m³.
After adding four additional blocks on the lid, the pressure rises from 4 atm to 8 atm (2 atm from the lid, 2 atm from the original blocks, and 4 atm from the new blocks).
Hence, The data established is,
P₁ = 4 atm
V₁ = 9 m³
P₂ = 8 atm
V₂ =?
Using Boyle's Law,
P₁ V₁ = P₂ V₂
Resolving for V₂,
V₂ = P₁ V₁ / P₂
Substituting values yields:
V₂ = (4 atm × 9 m³) ÷ 8 atm
V₂ = 4.5 m³
