1 Ca (s) + 2 HF (aq) → 1 CaF2 (s) +1 H2 (g) Identify the coefficient(s). Identify the subscript(s). What is the state of each of
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Response:
Here's my calculation
Clarification:
Assume the starting concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.
We need to determine the initial concentration of HI.
1. We will need a chemical equation with concentrations, so let's compile all the information in one location.
H₂ + I₂ ⇌ 2HI
I/mol·L⁻¹: 0.30 0.15 x
2. Calculate the concentration of HI
3. Plot the initial values
The graph below visualizes the initial concentrations as plotted on the vertical axis.
Answer:
The ratios arranged in ascending order are; The ratio of the mass of Y to X in XY2 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY3 divided by the mass of Y to X in XY, The ratio of the mass of Y to X in XY4 divided by the mass of Y to X in XY
1) Mass ratio = 3
2) Mass ratio = 2
3) Mass ratio = 4
Explanation:
Comprehensive calculations are displayed in the attachment.
Answer: Reaction 2 is a spontaneous one.
Explanation:
According to our understanding:
= +ve, meaning the reaction is non-spontaneous
= -ve, indicating the reaction is spontaneous
= 0, stating that the reaction is at equilibrium
For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.
Reaction 1:
Glucose + Pi ⟶ glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol
Reaction 2:
ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol