In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OAT

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In the first step of glycolysis, the given two reactions are coupled. reaction 1:reaction 2:glucose+Pi⟶glucose-6-phosphate+H2OAT

P+H2O⟶ADP+PiΔG=+13.8 kJ/molΔG=−30.5 kJ/mol reaction 1:glucose+Pi⟶glucose-6-phosphate+H2OΔG=+13.8 kJ/molreaction 2:ATP+H2O⟶ADP+PiΔG=−30.5 kJ/mol Answer the four questions about the first step of glycolysis. Is reaction 2 spontaneous or nonspontaneous?

Chemistry

1 answer:

lorasvet [2.7K] · Answer 1 · 2026-04-09T02:32:48+03:00

Answer: Reaction 2 is a spontaneous one.

Explanation:

According to our understanding:

$\Delta G$ = +ve, meaning the reaction is non-spontaneous

$\Delta G$ = -ve, indicating the reaction is spontaneous

$\Delta G$ = 0, stating that the reaction is at equilibrium

For a reaction to be classified as spontaneous, the Gibbs free energy must yield a negative value.

Reaction 1:

Glucose + Pi ⟶ glucose-6-phosphate + H₂O, ΔG = +13.8 kJ/mol $\rightarrow$

Reaction 2:

ATP + H₂O ⟶ ADP + Pi, ΔG = -30.5 kJ/mol $\rightarrow$

From this, we can conclude that ΔG being negative indicates that reaction 2 is indeed spontaneous.