a) 101%, b) 59.7%.The thermal decomposition of baking soda is represented by the equation: 2NaHCO3 → Na2CO3 + H2O + CO2. The calculation of moles from 1.555g of baking soda yields approximately 0.0185 moles. Utilizing the stoichiometry of the reaction, the theoretical yield is determined, and the percent yield is found to be 101%. Similarly, an unknown mixture of baking soda decomposing shows a percentage of NaHCO3 as 59.7%.
Answer: B.)
Explanation: Heat transfers from the pan to the surrounding environment.
Answer:
Explanation:
The relevant property is density.
I hope this helps! :)
Answer:
commensalism
(I hope I got that spelling correct)
Explanation:
when the bird only uses the tree for nesting and
the tree remains unaffected or unbothered by the bird's presence.
1) To start, we must establish the chemical equation for this combustion.
2C₈H₁₈ + 25O₂ ----> 16CO₂ + 18H₂O
2) Since we have the gasoline volume, we can convert it to grams using its density.
3.8 L is equal to 3800 mL.
To find grams: 3800 mL multiplied by 0.79 g/mL gives us 3002 grams.
3) We will convert grams into moles by utilizing the molar mass of gasoline.
The molar mass of C₈H₁₈ is calculated as (8 x 12.0) + (18 x 1.01) = 114.18 g/mol.
By converting, we find 3002 g is equal to 26.3 moles using (1 mol/ 114.18 grams).
4) We can now convert the moles of C₈H₁₈ to moles of water via the balanced equation.
26.3 moles of C₈H₁₈ is equal to 237 moles of H₂O (18 mol H₂O/ 2 moles C₈H₁₈).
5) We will convert moles to grams using the molar mass of water and then change this to kilograms.
The molar mass of H₂O is (2 x 1.01) + 16.0 = 18.02 g/mol.
Thus, 237 mol H₂O times (18.02 g/ 1 mol) gives us 4260 grams.
To convert to kilograms: 4260 grams equals 4.26 Kilograms.
