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avanturin
1 month ago
7

A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of $1.40. How ma

ny of each type of coin are in the bank?
Mathematics
1 answer:
zzz [11.8K]1 month ago
5 0

Answer:

4 nickels

12 dimes

Step-by-step explanation:

Dimes have a value of $0.10 each, while nickels are worth $0.05 each.

There are 8 more dimes than nickels. Let d represent the count of dimes and n represent nickels, so d equals n plus 8.

The total value of nickels and dimes is $1.40, giving the equation 0.10d + 0.05n = 1.40.

Combining equations:

d = n + 8

0.10d + 0.05n = 1.40

— Substitute the first into the second:

0.10(n + 8) + 0.05n = 1.40

Distribute terms:

0.8 + 0.10n + 0.05n = 1.40

Combine like terms:

0.8 + 0.15n = 1.40

Subtract 0.8 from both sides:

0.15n = 0.6

Divide both sides by 0.15:

n = 0.6 / 0.15 = 4

Since there are 8 more dimes, d = 4 + 8 = 12.

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