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avanturin
3 months ago
7

A piggy bank contains some dimes and nickels. There are 8 more dimes than nickels in the bank. There is a total of $1.40. How ma

ny of each type of coin are in the bank?
Mathematics
1 answer:
zzz [12.3K]3 months ago
5 0

Answer:

4 nickels

12 dimes

Step-by-step explanation:

Dimes have a value of $0.10 each, while nickels are worth $0.05 each.

There are 8 more dimes than nickels. Let d represent the count of dimes and n represent nickels, so d equals n plus 8.

The total value of nickels and dimes is $1.40, giving the equation 0.10d + 0.05n = 1.40.

Combining equations:

d = n + 8

0.10d + 0.05n = 1.40

— Substitute the first into the second:

0.10(n + 8) + 0.05n = 1.40

Distribute terms:

0.8 + 0.10n + 0.05n = 1.40

Combine like terms:

0.8 + 0.15n = 1.40

Subtract 0.8 from both sides:

0.15n = 0.6

Divide both sides by 0.15:

n = 0.6 / 0.15 = 4

Since there are 8 more dimes, d = 4 + 8 = 12.

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Response:

15.9

Detailed explanation:

\text{The formula of a distance between two points on a number line:}\\\\d=|a-b|\\\\\text{for}\ a\geq b:\ d=a-b\\=========================\\\\\text{We have}\ 4.7\ \text{and}\ -11.2.\ \text{Substitute:}\\\\d=4.7-(-11.2)=4.7+11.2=15.9

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2 months ago
The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [12445]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

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Part A

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As a result, for any x greater than \frac{1}{2}, the expression 2x-1 is positive

Part B

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