A catering company uses different functions to estimate the itemized costs for a party. The table below represents the included

2.8y + 6 + 0.2y = 5y – 14

Start by simplifying the left side:

3y + 6 = 5y - 14

Next, deduct 3y from both sides:

6 = 2y - 14

Add 14 to both sides:

2y = 20

Now, divide by 2:

y = 20 / 2

y = 10

To simplify the expression:
-(6 x^3 - 2 x + 3) - 3 x^3 + 5 x^2 + 4 x - 7

Start with - (6 x^3 - 2 x + 3) = -6 x^3 + 2 x - 3:
-6 x^3 + 2 x - 3 - 3 x^3 + 5 x^2 + 4 x - 7

Next, combine similar terms: -3 x^3 - 6 x^3 + 5 x^2 + 4 x + 2 x - 7 - 3 = (-3 x^3 - 6 x^3) + 5 x^2 + (4 x + 2 x) + (-7 - 3):
(-3 x^3 - 6 x^3) + 5 x^2 + (4 x + 2 x) + (-7 - 3)

-3 x^3 - 6 x^3 results in -9 x^3:
-9 x^3 + 5 x^2 + (4 x + 2 x) + (-7 - 3)

Combine 4 x and 2 x to get 6 x:
-9 x^3 + 5 x^2 + 6 x + (-7 - 3)

The operation -7 - 3 yields -10:
-9 x^3 + 5 x^2 + 6 x - 10

Factoring out -1 from -9 x^3 + 5 x^2 + 6 x - 10 leads to:
Final Answer: - (9 x^3 - 5 x^2 - 6 x + 10)

Answer:

Step-by-step explanation:

The total count of laptops, N = 20

Defective laptops, n = 3

The school is purchasing 2 laptops

Case 1:

Both purchased laptops are non-defective

Probability of selecting 2 non-defective laptops

The count of non-defective laptops equals 20 - 3 = 17

Overall laptop count = 20

Probability, P = 17/20 = 0.85

Case 2:

One laptop is found defective

The probability of choosing 1 defective and 1 non-defective laptop

P' = 3/20 x 17/19 = 0.134

Case 3:

Both laptops are defective

Choosing 2 laptops from 3 = 3 C 2 = 3

Selecting 2 from 20 = 20 C 2 = 190

The probability of selecting two defective laptops equals 3 / 190 = 0.0158

P'' =

Typically, the graph will have a labeled line such as f(x) = ... To find f(3), identify 3 on the x-axis, then trace vertically to the graph line and read the corresponding y-value.

Answer:

D

Step-by-step explanation:

When you multiply 3/4 by A, B, or C, it results in a decimal value; however, multiplying 3/4 by 8 yields 6, which is a whole number.