To determine the values of b that fulfill 3(2b+3)^2 = 36
we start with
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
Next, take the square root of both sides
(2b+3)} = (+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3
b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}
b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Thus,
the solutions for b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
To start, calculate the return for each
price per unit
Return = quantity sold x price
per unit
Return1 = 5000 units x Php 900
Return1 = Php 4,500,000
Next, figure out the return for the other price per
unit
Return2 = quantity sold x
price per unit
Return2 = (5000 + 1500 units) x (
Php 900 – 100)
Return2 = Php 5,200,000
Thus, a price of Php 800 per unit will result in a higher return.
Answer:
Error made by Andrew: He identified incorrect factors based on the roots.
Step-by-step explanation:
The roots of the polynomial consist of: 3, 2 + 2i, 2 - 2i. By the factor theorem, if a is a root of the polynomial P(x), then (x - a) must be a factor of P(x). According to this premise:
(x - 3), (x - (2 + 2i)), (x - (2 - 2i)) represent the factors of the polynomial.
<pBy simplification, we obtain:
(x - 3), (x - 2 - 2i), (x - 2 + 2i) as the respective factors.
This is where Andrew's mistake occurred. Factors should always be in the form (x - a), not (x + a). Andrew expressed the complex factors incorrectly, resulting in an erroneous conclusion.
Thus, the polynomial can be expressed as:
From AA3+2=AAA, it follows that 3+2 equals A, so A must be 5.
Given CC6+6=CBB, since 6+6 equals 12, the final digit has to be 2, making B=2. Additionally, adding 6 to 6 increases the tens digit by one, meaning B is one more than C, so C=1 (since 2-1=1). Therefore, ABC equals 521.
Answer:
No, she did not.
Step-by-step explanation:
Calculate the total expense for the food and then divide by 6. You will see that she falls short.
