Answer:
The response to your inquiry is: 15 m/s²
Explanation:
Equation x = at³ - bt² + ct
a = 4.1 m/s³
b = 2.2 m/s²
c = 1.7 m/s
First we calculate x at t = 4.1 s
x = 4.1(4.1)³ - 2.2(4.1)² + 1.7(4.1)
x = 4.1(68.921) - 2.2(16.81) + 6.97
x = 282.58 - 36.98 + 6.98
x = 252.58 m
Now we calculate speed
v = x/t = 252.58/ 4.1 = 61.6 m/s
Finally
acceleration = v/t = 61.6/4.1 = 15 m/s²
<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.
For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26
For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
Response:
2.5kN.m
Details:
Torque relates directly to the pitch diameter
= Ta/Tb= Da/Db
For 120/Tb= 0.25/0.5
This gives Tb= 2.469kN.m, roughly 2.5kN.m
Answer:
The molar mass of the metal in grams per mole is calculated to be 8.87.
Explanation:
Initially, we can consider a sample of the compound weighing 100 g. This results in:
- 52.92% metal: 52.92 g M
- 47.80% oxygen: 47.80 g O
By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:

moles of oxygen=2.9875
The formula for the metal oxide indicates that:
2 M⁺³ + 3 O²⁻ ⇒ M₂O₃
From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:

Given 52.92 g of metal in the sample, the molar mass of the metal is:

molar mass≅ 8.87 g/mol
The molar mass of the metal in grams per mole is 8.87.
The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.
The force exerted by the car on the bug is identical to the force the bug applies back on the car.