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1 month ago

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Three point charges are arranged on a line. Charge q3=+5.00x10^-9C and is at the origin. Charge q2=-3.00x10^-9C and is at x=+4.0

0cm. Charge q1 is at x=+2.00cm. What is the magnitude and sign (+ or -) for q1 if the net force on q3 is zero?
A. 0.750 nC
B. 0.520 nC
C. 0.975 nC
D. 0.000 nC

2 answers:

Yuliya22 [3.3K]1 month ago

5 0

Answer:

A. 0.750 nC

Explanation:

The net electric force acting on q3 is stated to be 0,

therefore, the electric field generated by q1 at the origin equals the electric field produced by q2 at the origin

$k\frac{q_{1} }{r_{1} ^{2} } =k\frac{q_{2} }{r_{2} ^{2} }$

$\frac{q_{1} }{r_{1} ^{2} } =\frac{q_{2} }{r_{2} ^{2} }$

${q_{1} } } =\frac{q_{2} }{r_{2} ^{2} }*{r_{1} ^{2}$

= ( -3.00x10^-9 x 2^2)/ 4^2

=-0.750nC

This indicates it must possess a negative charge

Sav [3.1K]1 month ago

5 0

Answer:

The result is 0.750 NC

Explanation:

I am also taking the same test

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