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Yuki888
3 months ago
7

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and

perpendicular components, respectively, of this force with respect to the ground?
Physics
2 answers:
Softa [3K]3 months ago
3 0

Explanation:

It is stated that:

The force acting on the sled is F = 110 N.

The angle with the ground is 30 degrees.

This force has two components: one parallel and the other perpendicular. They are referred to as F_x\ and\ F_y

Parallel component:

F_x=F\ cos\theta

F_x=100\ cos(30)

F_x=86.6\ N

Perpendicular component:

F_y=F\ sin\theta

F_y=100\ sin(30)

F_y=50\ N

Thus, the components of this force relative to the ground are 86.6 N for the parallel and 50 N for the perpendicular. This is the final answer.

Softa [3K]3 months ago
3 0
<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.

For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26

For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
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Answer:

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Explanation:

The question states that

    The radius measures  R

     The length is L

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The volume charge density is mathematically expressed as

      \rho = nq

The surface charge density is mathematically expressed as

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substituting for  \rho

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2 months ago
You decide it is time to clean your pool since summer is quickly approaching. Your pool maintenance guide specifies that the chl
Yuliya22 [3333]

Answer:

Cl2 concentration: 1,048 ppm

Explanation:

Molarity (M) is a unit that indicates how many moles of a substance are in one liter of solution, while ppm is similar to mg/L, representing the mass of the substance per liter. To convert M to ppm, we need to consider both mass and volume. The volume remains in liters in both cases, so no adjustments are needed there. The challenge arises when converting moles from molarity to milligrams for the mg/L conversion to find ppm.

First, we must recognize that the substance in question is Cl2, prompting the need to connect mole quantity to its mass. Referring to the periodic table, we find the atomic weight of Cl is 35.4 g/mole. This relationship allows us to establish moles' mass, as shown in the following equation:

mass=mole*atomic mass

We already know the moles of Cl2 in the solution is (moles=2.96x10^-5). Substituting this value, we can calculate:

m=2,96x10^-5 moles*35,4 g/mole\\ m=1,048x10^-3 g

Keep in mind that we're discussing the mass found per liter of solution, which gives us 1.048x10^-3 g/L. We previously established that ppm equals mg/L, so we need to convert grams to milligrams:

1 g = 1000 mg

Now multiplying both sides by 1.048x10^-3:

1 * 1.048x10^-3 g = 1000 * 1.048x10^-3 mg

Thus, 1,048x10^-3 g translates to 1,048 mg.

This amount of mass detected in one liter indicates that the concentration of the substance in the solution is:

1,048 mg/L

Since we know that mg/L=ppm, the conclusion is:

1,048 ppm

4 0
3 months ago
g Suppose Howard is pulling a bucket of bricks up along the side of a building with a rope. The bricks have a mass of 20 kg and
ValentinkaMS [3465]
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1 month ago
"What will the pressure inside the container become if the piston is moved to the 1.60 L mark while the temperature of the gas i
Softa [3030]

Esta pregunta está incompleta, la pregunta completa es;

La figura muestra un recipiente sellado en la parte superior por un pistón móvil. Dentro del recipiente hay un gas ideal a 1.00 atm. 20.0°C y 1.00 L.

"¿Cuál será la presión dentro del recipiente si el pistón se mueve hasta la marca de 1.60 L mientras se mantiene constante la temperatura del gas?"

Answer:

la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L manteniendo constante la temperatura del gas

Explicación:

Dado que;

P₁ = 1.00 atm

P₂ =?

V₁ = 1 L

V₂ = 1.60 L

la temperatura del gas se mantiene constante

sabemos que;

P₁V₁ = P₂V₂

por lo que hacemos la sustitución

1 × 1 = P₂ × 1.60

P₂ = 1 / 1.60

P₂ = 0.625 atm

Por lo tanto, la presión dentro del recipiente será 0.625 atm si el pistón se mueve hasta la marca de 1.60 L mientras la temperatura del gas se mantiene constante

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