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Yuki888
1 month ago
7

Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and

perpendicular components, respectively, of this force with respect to the ground?
Physics
2 answers:
Softa [3K]1 month ago
3 0

Explanation:

It is stated that:

The force acting on the sled is F = 110 N.

The angle with the ground is 30 degrees.

This force has two components: one parallel and the other perpendicular. They are referred to as F_x\ and\ F_y

Parallel component:

F_x=F\ cos\theta

F_x=100\ cos(30)

F_x=86.6\ N

Perpendicular component:

F_y=F\ sin\theta

F_y=100\ sin(30)

F_y=50\ N

Thus, the components of this force relative to the ground are 86.6 N for the parallel and 50 N for the perpendicular. This is the final answer.

Softa [3K]1 month ago
3 0
<span>A force of 110 N is applied at an angle of 30</span>°<span> to the horizontal. Because the force does not align directly either vertically or horizontally with the sled, it can be broken down into two components based on sine and cosine.

For the component parallel to the ground:
x = rcos</span>β
<span>x = 110cos30</span>°
<span>x = 95.26

For the component perpendicular to the ground:
y = rsin</span>β
<span>y = 110sin30</span>°
<span>y = 55</span>
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