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SIZIF
3 months ago
12

A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w

hat is its velocity as it leaves his hand?
Physics
1 answer:
Keith_Richards [3.2K]3 months ago
4 0
25.82 m/s Explanation: Given: Force applied by the baseball player; F = 100 N Distance the ball travels; d = 0.5 m Mass of the ball; m = 0.15 kg To find the velocity at which the ball is released, we will equate the work done with the kinetic energy involved. It's important to recognize that work done reflects the energy the baseball player has used. Thus, the relationship can be represented as follows: F × d = ½mv² 100 × 0.5 = ½ × 0.15 × v² Solving gives: v² = (2 × 100 × 0.5) / 0.15 v² = 666.67 v = √666.67 v = 25.82 m/s.
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