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SIZIF
3 days ago
12

A baseball player exerts a force of 100 N on a ball for a distance of 0.5 mas he throws it. If the ball has a mass of 0.15 kg, w

hat is its velocity as it leaves his hand?
Physics
1 answer:
Keith_Richards [2.2K]3 days ago
4 0
25.82 m/s Explanation: Given: Force applied by the baseball player; F = 100 N Distance the ball travels; d = 0.5 m Mass of the ball; m = 0.15 kg To find the velocity at which the ball is released, we will equate the work done with the kinetic energy involved. It's important to recognize that work done reflects the energy the baseball player has used. Thus, the relationship can be represented as follows: F × d = ½mv² 100 × 0.5 = ½ × 0.15 × v² Solving gives: v² = (2 × 100 × 0.5) / 0.15 v² = 666.67 v = √666.67 v = 25.82 m/s.
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Energy is observed in two basic forms: potential and kinetic. Which of the following correctly matches these forms with a source
Ostrovityanka [2204]

Answer:

option C

Explanation:

The appropriate selection is option C

Kinetic energy refers to energy stemming from the movement of an object.

Potential energy is associated with the position of an object.

Option A is incorrect as potential energy arises from an object's location.

Option B is misclassified; it should describe potential energy instead of kinetic.

Option D indicates that the motion of individual molecules generates kinetic energy, not potential energy.

Thus, the correct option indicates that the covalent links within a sugar molecule represent potential energy due to the arrangement of the bond.

4 0
22 days ago
The wavelength of light is 5000 angstrom. Express it in nm and m.
serg [2593]

Answer:

1 angstrom equals 0.1 nm.

To convert 5000 angstroms: 5000 angstrom = 5000 / 1 × 0.1 nm.

= 500 nm

1 \:  angstrom = 1 \times  {10}^{ - 10} m

To express 5000 angstroms in meters: 5000 angstrom = 5000 × 1 × 10^-10.

= 5 × 10^-7 m

Hope this explanation is useful for you.

7 0
1 month ago
To avoid an accident, a driver steps on the brakes to stop a 1000-kg car traveling at 65km/h. if the braking distance is 35 m, h
Maru [2355]
Initially, we need to calculate the acceleration required for the car to halt from its initial speed based on the distance traveled. This can be done using the formula,
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where a represents acceleration, d is distance, and Vf and Vi are the final and initial speeds respectively. Plugging in the known quantities,
           2(a)(35 m) = (0 m/s)² - ((65 km/h) x (1000 m/ 1 km) x (1 hr / 3600 s))²
The resulting acceleration is −4.66 m/s².
To calculate the force required to stop the car, we multiply the mass by the acceleration. This calculation yields -4,660 N, and we take the absolute value, which is 4,660 N. 
6 0
28 days ago
At a location where the acceleration due to gravity is 9.807 m/s2, the atmospheric pressure is 9.891 × 104 Pa. A barometer at th
serg [2593]

Answer:

8616.7468 \ kg/m^3

Explanation:

The measurement of pressure is indicated as p=\rho gh where p denotes the pressure, \rho signifies density, and h represents height

Given values include pressure p=9.891\times 10^4\ Pa, gravity's acceleration g=9.9870\ m/sec^2, and height =1.163 m

\rho =\frac{p}{gh}=\frac{9.891\times 10^4}{9.870\times 1.163}=8616.7468 \ kg/m^3

5 0
8 days ago
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Answer:

1. The sun is moved away from the Earth by an equal force exerted by the Earth.

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17 days ago
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