Response: a. The mirrors and eyepiece of a large telescope are designed with spring-loaded components to quickly return to a predetermined position.
Justification:
Adaptive optics refers to a technique employed by various astronomical observatories to compensate in real-time for the atmospheric turbulence that impacts astronomical imaging.
This is executed by integrating advanced deformable mirrors into the telescope's optical pathway, operated by a set of computer-controlled actuators. This allows for obtaining clearer images despite the atmospheric fluctuations that create distortions.
It is crucial to note that this process requires a moderately bright reference star located closely to the object being studied.
However, locating such stars is not always feasible, prompting the use of a strong laser beam directed at the upper atmosphere to create artificial stars.
<span>Answer:
The correct response is
simply sum the two kinetic energies:
E = (1/2)mv^2 + (1/2)mv^2</span>
Answer:
The snowball's speed after the impact is 3 m/s
Explanation:
Given the following:
mass of each ball
m₁ = 0.4 Kg
m₂ = 0.6 Kg
initial speed of both balls = v₁ = 15 m/s
Speed of 1 Kg mass post-collision =?
Applying conservation of momentum
m₁ v₁ - m₂ v₁ = (m₁+m₂) V
A negative velocity indicates that the second ball moves in the opposite direction.
0.4 x 15 - 0.6 x 15 = (1) V
Therefore,
V = - 3 m/s
Consequently,
The snowball's speed following the collision is 3 m/s
Response:
A=0.199
Clarification:
We know that
Mass of spring=m=450 g=
Where 1 kg=1000 g
Frequency of oscillation=
Energy for oscillation is 0.51 J
To determine the amplitude of oscillations.
Energy for oscillator=
Where 
=Angular frequency
A=Amplitude
Using the formula
Therefore, the amplitude of oscillation=A=0.199
Answer:
Incomplete question: "Each block has a mass of 0.2 kg"
The velocity of the center of mass for the two-block system just prior to their collision is 2.9489 m/s
Explanation:
Provided information:
θ = angle of the surface = 37°
m = mass of each block = 0.2 kg
v = speed = 0.35 m/s
t = collision time = 0.5 s
Question: What is the velocity of the center of mass for the two-block system right before the blocks collide, vf =?
Change in momentum:
It’s essential to calculate the required force:
Here, g = acceleration due to gravity = 9.8 m/s²
