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ss7ja
1 month ago
10

Calculate the average time it took the car to travel 0.25 and 0.50 meters with three washers attached to the pulley. Record the

averages, rounded to two decimal places, in Table C of your Student Guide. What is the average time it took the car to travel 0.25 meters? seconds What is the average time it took the car to travel 0.50 meters?
Physics
2 answers:
inna [3.1K]1 month ago
7 0

Answer:

The duration it took for the car to cover 0.25 meters was 2.23 seconds.

The duration for the car to travel 0.50 meters was 3.13 seconds.

Glad to assist:)

kicyunya [3.2K]1 month ago
4 0

Answer:

.25 meters = 1.34 seconds

.50 meters = 1.89 seconds

Explanation: I made an error and those were the right outcomes shown.

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50 POINTS! A Boy throws a ball horizontally a distance of 22m downrange from the top of a tower that is 20.0m tall. What is his
Softa [3030]

At time t, the ball's horizontal and vertical velocities can be represented as

v_x=v_{xi}

v_y=v_{yi}-gt

However, since the ball is thrown horizontally, we have v_{yi}=0. The horizontal and vertical positions at time t are

x=v_{xi}t

y=20.0\,\mathrm m-\dfrac g2t^2

The ball travels a distance of 22 m horizontally from the throw point, thus

22\,\mathrm m=v_{xi}t

With this, we determine that the time for the ball to reach the ground is

t=\dfrac{22\,\rm m}{v_{xi}}

When it touches down, y=0 and

0=20.0\,\mathrm m-\dfrac{9.8\frac{\rm m}{\mathrm s^2}}2\left(\dfrac{22\,\rm m}{v_{xi}}\right)^2

\implies v_i=v_{xi}=11\dfrac{\rm m}{\rm s}

7 0
21 day ago
1) Compute the travel time ratio of the other objects to the hollow cylinder. 2) Discuss how the travel time ratio of solid cyli
inna [3103]

Answer:

(1) Utilize the information provided in Table R2 and the error propagation principle to calculate the travel time ratio (with errors) of the other objects compared to the hollow cylinder? ℎ?. Complete Table R5 below. [6] Table R5 Solid cylinder Billiard ball Racquetball?? ℎ? ± ± ± (2) Examine how the solid cylinder's ratio to the hollow cylinder supports or contradicts the theoretical ratio in Eq. (8) stated in the manual. Compute the percentage error and discuss. [4] Answer: (3) Based on the travel time ratio, determine (i) if the billiard ball is solid or hollow, and (ii) if the racquetball is solid or hollow. Provide your reasoning. (Answers may vary if your measurements lack sufficient clarity.) [4]

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PHYS2125 Physics Laboratory I ©2018 Kuei Sun The University of Texas at Dallas 5 Answer: (4) Identify the object in Table R2 with the highest SEOM. Provide reasoning for the relatively high SEOM and suggest improvements. [3] (5) Discuss TWO potential systematic errors in measurement. [3] Answer: **Please attach your calculation details. Use as many pages as needed; calculations that reflect your understanding may earn partial credit. **Ensure your workspace and equipment are identical to how you left them.

Explanation:

6 0
1 month ago
When you apply the torque equation ∑τ = 0 to an object in equilibrium, the axis about which torques are calculated:
Softa [3030]

Answer:

option D.

Explanation:

The correct choice is option D.

For an object in equilibrium, the torque measured at any point will be zero.

An object is deemed to be in equilibrium when the net moment acting on it equals zero.

If the object experiences a net moment not equal to zero, it will rotate and will not remain stable.

3 0
1 month ago
The acceleration due to gravity on the moon is 1.6 m/s2, about a sixth that of Earth’s. Which accurately describes the weight of
kicyunya [3294]

Response:

The question is not fully provided; here is the complete context:

Gravity's acceleration on the moon is 1.6 m/s², roughly one-sixth that of Earth's. What is the accurate description of an object's weight on the moon?

A. An object on the moon is lighter by a factor of 1/6 compared to Earth.

B. An object on the moon is heavier by a factor of 1/6 compared to Earth.

C. An object on the moon is six times lighter than on Earth.

D. An object on the moon is six times heavier than on Earth.

The correct choice is:

An object on the moon is six times lighter than on Earth. (C)

Explanation:

The acceleration resulting from gravity indicates how a gravitational force impacts an object, causing it to accelerate. This is a vectorial quantity because it possesses both magnitude and direction, measured in the unit of m/s². On Earth, this gravitational acceleration is represented by the letter g and its value is approximately 9.8m/s².

The larger size of the Earth in comparison to the moon causes its gravitational acceleration to be about six times greater than that of the moon, resulting in the moon's gravitational acceleration being approximately 1.6m/s².

Next, weight refers to the product of mass and gravity's acceleration. This reflects the gravitational pull acting upon a mass, which is also measured in Newtons, similar to force.

Weight = m × g (N)

From the weight formula, we can see that weight corresponds directly to mass and gravitational acceleration:

weight ∝ mass;

weight ∝ gravitational acceleration.

This implies that if gravitational acceleration increases, weight increases as well, and vice versa.

For instance, let's calculate the weights of a 10kg object on both Earth and the moon.

Gravitational acceleration on Earth (g₁) = 9.8m/s².

Gravitational acceleration on the moon (g₂) = 1.6m/s².

On Earth:

weight = m × g₁ = 10 × 9.8 = 98 N.

On the moon:

weight = m × g₂ = 10 × 1.6 = 16 N.

From the above example, since the acceleration due to gravity on the moon is 1/6 that of Earth, the weight of a 10kg object on the moon is approximately six times lighter (16 N) than its weight on Earth (98 N).

5 0
1 month ago
Read 2 more answers
The superhero Green Lantern steps from the top of a tall building. He falls freely from rest to the ground, falling half the tot
serg [3582]
1) The initial velocity is zero. 2) We consider the downward direction as positive.
3) h = 25.66 m.
Explanation:
This is a problem of free fall.
1) In free fall, the initial velocity starts at zero, and acceleration remains constant throughout, equal to gravity.
2) It's common to choose downward as the positive direction.
3) For the latter part of the fall:
y₀ - y = h/2 when t = 1 s,
y = y₀ + v₁ t + ½ g t²,
with v₁ being the initial velocity at height h / 2,
v₁ t = (y - y₀) - ½ g t².
v₁ = h / 2 - ½ g t².
Now, let's set up the first interval equation:
v₁² = v₀² + 2 g (y₁ - y₀).
Since in this case v₀ = 0,
v₁² = 2 g (y₁ - y₀) = 2g h/2.
Next, our equations become:
v₁² = (h/2 - g/2)² and v₁² = (2g h / 2).
Thus, solving the quadratic equation leads to:
h² - 3 g h + g² = 0, which simplifies to h² - 29.4 h + 96.04 = 0.
Finally, solving this yields h = 25.66 m as the height.
6 0
1 month ago
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