Answer:
1)
2)
Explanation:
Projectile Motion
When an object is projected near the surface of the Earth at an angle to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.
The height of a projectile can be calculated using
where represents the initial height from ground level,
is the vertical component of the initial velocity, and t is the elapsed time.
The vertical speed component is expressed as
1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of .
The peak height is attained when , which allows us to compute the time to reach that height.
Solving for
Thus, the maximum height reached is
We know this value is equal to 8 meters
Continuing with the calculations for
Substituting known values yields
2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate
Answer:
Induced EMF is 2 x 10⁻³ volts
Explanation:
B = strength of the magnetic field aligning with the loop's axis = 1 T
= area change rate of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = the angle formed by the magnetic field and area vector = 0
E = the induced EMF across the loop
EMF can be calculated using the formula
E = B
E = (1) (20 x 10⁻⁴ )
E = 2 x 10⁻³ volts
E = 2 mV
Answer:
The initially bent young tree has been straightened by adjusting the tensions of the three guy wires to AB = 7 lb, AC = 8 lb, and AD = 10 lb. Please calculate the force and moment reactions at the trunk's base point O, disregarding the weight of the tree.
C and D are situated 3.1' from the y-axis, while B and C are located 5.4' from the x-axis, and A has a height of 5.2'.
Explanation:
Refer to the attached image.
Answer:
The molar mass of the metal in grams per mole is calculated to be 8.87.
Explanation:
Initially, we can consider a sample of the compound weighing 100 g. This results in:
By utilizing the molar mass of oxygen, which is 16 g / mol, we can determine the quantity of moles of oxygen in the sample via the rule of three:
moles of oxygen=2.9875
The formula for the metal oxide indicates that:
2 M⁺³ + 3 O²⁻ ⇒ M₂O₃
From the previous equation, it is evident that 3 oxygen ions are necessary to react with 2 metal ions. Hence:
Given 52.92 g of metal in the sample, the molar mass of the metal is:
molar mass≅ 8.87 g/mol
The molar mass of the metal in grams per mole is 8.87.
The value that most closely corresponds to this is Beryllium (Be), which has an atomic mass of 9.0122 g / mol.