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Akimi4
1 month ago
6

Tony's Tires has shown growth over the last month that follows the

Mathematics
1 answer:
PIT_PIT [12.4K]1 month ago
4 0

Response:

Detailed explanation:

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PIT_PIT [12445]
B. The correct ratio is sen α = BC/b. Step-by-step explanation: Trigonometric identities are utilized for resolving problems involving right angles. In any right-angled triangle, the side opposite to the angle is known as the opposite side, while the adjacent side runs parallel to the angle, ultimately leading to the longest side, called the hypotenuse.
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23 days ago
The graphs below have the same shape. The equation of the blue graph is f(x)=x^2. Which of these is the equation of the red grap
tester [12383]
We observe that
the vertex of f(x) is located at the point (0,0)
and
the vertex of g(x) is situated at (0,5)

thus,
(x,y) in f(x)  becomes -------> (x,y+5) in g(x)
g(x)---------> f(x)+5

g(x)=x²+5

the answer is
g(x)=x²+5

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1 month ago
A flat circular plate has the shape of the region x2 + y2≤1. The plate, including the boundary where x2 + y2 = 1, is heated such
Leona [12618]
Setting both partial derivatives to zero results in a single critical point at (x,y)=\left(\dfrac12,0\right), located within the unit disk.

At this given point, the derivative value of the Hessian matrix is

|H|=\begin{vmatrix}T_{xx}&T_{xy}\\T_{yx}&T_{yy}\end{vmatrix}=\begin{vmatrix}2&0\\0&4\end{vmatrix}=8>0

and the second-order partial derivative with respect to x yields

T_{xx}\bigg|_{(x,y)=(1/2,0)}=2>0

This suggests that the critical point represents a local minimum, marking it as the coldest area on the plate with a temperature of T\left(\dfrac12,0\right)=-\dfrac14.

To find the hottest area on the plate, it must be located along the boundary. Let x=\cos\theta and y=\sin\theta, so that

T(x,y)=T(\theta)=\cos^2\theta+2\sin^2\theta-\cos\theta
T(\theta)=\dfrac32-\cos\theta-\dfrac12\cos2\theta

Thus, the plate's boundary (the circle x^2+y^2=1) is treated as a single variable function \theta examined over \theta\in[0,2\pi). A single differentiation gives

T'(\theta)=\sin\theta+\sin2\theta=0
\implies\theta=0,\theta=\dfrac{2\pi}3,\theta=\pi,\theta=\dfrac{4\pi}3

You will discover that T(\theta) achieves three extrema on the interval (0,2\pi), with relative maxima occurring at \theta=\dfrac{2\pi}3 and \theta=\dfrac{4\pi}3, and a relative minimum at \theta=\pi (and \theta=0, if you wish to include that).

Our minimum has already been identified inside the plate - which you can check to have a lower temperature than at the points noted by T(\theta) - and we identify two maxima at \theta=\dfrac{2\pi}3 and \theta=\dfrac{4\pi}3, both showing a maximum temperature of T=\dfrac94.

Reverting to Cartesian coordinates, these points match up with \left(-\dfrac12,\pm\dfrac{\sqrt3}2\right).
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22 days ago
What is the main reason Dylan uses the word uses the word “lonesome” to describe Hattie Carroll’s death?
lawyer [12517]

The correct answer is B. No one stood up for her

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2 months ago
RANDOMLY CHOOSING TWO POTENTIAL CLIENTS
Svet_ta [12734]
Let Jacob, Carol, Geraldo, Meg, Earvin, Dora, Adam, and Sally be denoted as J, C, G, M, E, D, A, and S respectively. In part IV, we need to identify the pairs of potential clients that could potentially be selected. The sample space consists of all possible outcomes, therefore we create a set of all valid pairs, listed as follows: {(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S), (C, G), (C, M), (C, E), (C, D), (C, A), (C, S), (G, M), (G, E), (G, D), (G, A), (G, S), (M, E), (M, D), (M, A), (M, S), (E, D), (E, A), (E, S), (D, A), (D, S), (A, S)}. We can verify the number of elements in the sample space, n(S) is 1+2+3+4+5+6+7=28. This gives us the answer to the first question: What is the count of pairs of potential clients that can be randomly selected from the pool of eight candidates? (Answer: 28.) II) What is the chance of a certain pair being chosen? The chance of picking a specific pair is 1/28, as there’s just one way to select a particular pair out of the 28 possible options. III) What is the probability that the selected pair consists of Jacob and Meg or Geraldo and Sally? The probability of selecting (J, M) or (G, S) is 2 out of 28, which equates to 1/14. Answers: I) 28 II) 1/28 ≈ 0.0357 III) 1/14 ≈ 0.0714 IV) {(J, C), (J, G), (J, M), (J, E), (J, D), (J, A), (J, S), (C, G), (C, M), (C, E), (C, D), (C, A), (C, S), (G, M), (G, E), (G, D), (G, A), (G, S), (M, E), (M, D), (M, A), (M, S), (E, D), (E, A), (E, S), (D, A), (D, S), (A, S).}
6 0
1 month ago
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