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allsm
4 days ago
15

A local weather enthusiast wants to see if the last five summers have been warmer than normal for Eloy, Arizona. From the Nation

al Oceanic and Atmospheric Administration (NOAA), he knows the 30-year average for July was 90° with a standard deviation of 2.1°. The last five summers recorded have an average of 92°. If he uses a = 2.5%, which of the following would be valid based on the data he has gathered?
A) He can conclude that the summers have been warmer than the 30-year average.
B) He can conclude that the summers will continue to be warmer for the next 10 years.
C) He does not have enough information to make a decision.
D) The average for the last five years fits with the 30-year average.
Mathematics
2 answers:
PIT_PIT [9.1K]4 days ago
6 0
Based on the data collected by the local weather enthusiast, the valid answer is D. The average of the past five years aligns with the 30-year average. The recorded average for the five summers is 92 degrees, and with a standard deviation of 2.1 degrees, it fits within the 30-year context.
Leona [9.2K]4 days ago
5 0
The average temperature for July over the past 30 years in Eloy and Arizona is 90°. The standard deviation is 2.1°. This implies that the temperature over these 30 years spans from 90° - 2.1° to 90° + 2.1°, which equals 87.9° to 90°. The average for the last five summers in Eloy and Arizona is 92°. To calculate the reduction, which is 2.5% from 92, we find that 89.70° is within the 87.9° to 90° range. Thus, it can be concluded that the two averages are likely identical.
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a) The area of a rectangle is calculated by multiplying the length by the width:
   A = l·w

This formula allows us to express the width in terms of area and length. By dividing A by l, we find
   A/l = w

We also recognize that the perimeter of a rectangle is the total length around it.
   P = l + w + l + w
   P = 2(l + w)
We aim to rewrite the perimeter formula to isolate l on one side, using the expression for w derived earlier.
   P = 2(l + A/l)

By substituting the known value for A, we can express p(l) as
   p(l) = 2(l + 25/l)
   p(l) = 2l + 50/l


b)
For lengths exceeding widths, we have
   l > w
   l > A/l
   l² > A
   l > √A
   l > √25

This indicates that the domain of p(l) is
   l ∈ (5, ∞)..... meters
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1 month ago
If m + n = 7 and 2n - 3m = 6, what is the value of 3n - 2m ?
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Given the equation m + n = 7, we can express m as 7 - n. Then we can rewrite the second equation as 2n - 3(7 - n) = 6. Solving this leads us to find n = -3, which gives us m = 10. We can then calculate 3(-3) + 2(10), resulting in the value of 11.
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Janet is drawing the path formed by the parametric equations x=2+3 sin t and y=1-1/2cos t. Which curve did she draw??
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Sin²t +cos²t =1

<span>x=2+3 sin t
sin t=(x-2)/3

</span><span>y=1-1/2cos t
y-1= - (cos t)/2
cos t =-(y-1)/(1/2)

</span>(x-2)²/3² + (y-1)²/(1/2)² = 1
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19 hours ago
Your company manufactures two models of speakers, the Ultra Mini and the Big Stack. Demand for each depends partly on the price
PIT_PIT [9121]

Answer:

1. For Ultra Minis, the equation is p1 = (100,000 - p2)/1,600

2. For Big Stack, the equation is p2 = (150,000 - p1)/1,600

Step-by-step explanation:

Given the demand equations which reflect an inverse correlation between price and the quantity demanded, the placeholders in both equations should be interpreted as negative signs. So, we can rewrite the functions as:

q1(p1, p2) = 100,000 - 800p1 + p2................................ (1)

q2(p1, p2) = 150,000 + p1 - 800p2............................... (2)

Total revenue (TR) in economics is defined as the quantity sold multiplied by the price, hence we can calculate the total revenues for Ultra Mini (TRq1) and Big Stack (TRq2) by multiplying equations (1) and (2) by p1 and p2 respectively:

For q1:

TRq1 = p1 * q1(p1, p2) = p1(100,000 - 800p1 + p2)

TRq1 = 100,000p1 - 800p1^2 + p1p2.......................... (3)

For q2:

TRq2 = p2 * q2(p1, p2) = p2(150,000 + p1 - 800p2)

TRq2 = p2150,000 + p1p2 - 800p2^2........................ (4)

To find marginal revenues (MR), we will differentiate each of these revenue functions:

For equation (3), taking the partial derivative with respect to p1 and setting it to zero:

MR = dTRq1/dp1 = 100,000 - 2(800p1) + p2 = 0

= 100,000 - 1,600p1 + p2 = 0

Rearranging gives:

1,600p1 = 100,000 - p2

p1 = (100,000 - p2)/1,600.................................. (5)

In equation (5), p1 represents the price that maximizes Ultra Mini's total revenue.

Now differentiating equation (4) with respect to p2 and setting it to zero:

MR = dTRq2/dp2 = 150,000 + p1 - 2(800p2) = 0

= 150,000 - 1,600p2 + p1 = 0

Rearranging yields:

1,600p2 = 150,000 - p1

p2 = (150,000 - p1)/1,600.................................... (6)

The value for p2 in equation (6) is the price that optimizes the total revenue for Big Stack.

Thus, the optimal prices for maximizing total revenue are p1 = (100,000 - p2)/1,600 for Ultra Minis and p2 = (150,000 - p1)/1,600 for Big Stack.

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1 month ago
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Answer:

x = StartFraction negative

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Step-by-step explanation:

0 = – 3x2 – 2x + 6

This can also be expressed as

– 3x2 – 2x + 6 = 0

Using the quadratic formula, we have:

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In this case,

a = -3

b = -2

c = 6

x = -(-2) ± √((-2)² - 4(-3)(6)) / 2(-3)

x = StartFraction negative

(negative 2) plus or minus StartRoot (negative 2) squared minus 4 (negative 3)(6) EndRoot Over 2(negative 3) EndFraction

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1 month ago
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