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Artist 52
7 days ago
8

There is a mound of g pounds of gravel in a quarry. Throughout the day, 400 pounds of gravel are added to the mound. Two orders

of 900 pounds are sold and the gravel is removed from the mound. At the end of the day, the mound has 1,300 pounds of gravel.
Mathematics
1 answer:
PIT_PIT [11.9K]7 days ago
3 0

Question is Incomplete; Complete question is given below;

A pile of g pounds of gravel exists in a quarry. During the day, 400 pounds of gravel is added to the pile. Two orders of 900 pounds are removed, resulting in the mound holding 1,500 pounds of gravel by day's end. Formulate the equation that accurately illustrates this scenario.

Answer:

The equation that best represents the situation is g+400-1800=1300.

Step-by-step explanation:

Given:

Initial gravel amount = 'g'.

Currently Given:

Throughout the day, 400 pounds of gravel is added to the pile.

Thus we can conclude;

Gravel amount after addition = g+400

Also given:

Two orders of 900 pounds are sold and the gravel is taken from the pile.

Hence, two orders of 900 pounds = 2\times 900 = 1800 \ pounds

This leads us to state;

Gravel amount post-removal = g+400-1800

Now Given:

Remaining gravel at the end of day = 1300 pounds.

Therefore, we derive that;

g+400-1800=1300

Consequently, the equation that best describes the scenario is g+400-1800=1300.

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