Answer:
1128.
Explanation:
The phenotype for dominant tasters is 1482.
The phenotype for recessive tasters = 2400 – 1482 = 918.
Recessive phenotypes = 2400 – 1482 = 918.
The frequency of the recessive phenotype = q² = 918 / 2400 = 0.38.
The frequency of the recessive allele q = √0.38 = 0.62.
For the dominant allele frequency, p = 1-q = 1- 0.62 = 0.38.
The heterozygous frequency = 2pq = 2 × 0.38 × 0.62 = 0.47.
The number of heterozygous individuals within the population = 0.47 × 2400 = 1128.
Thus, the result is 1128.
The solute potential is indicated by the formula P = -iCRT, with i representing the ionization constant, C being the molar concentration, R as the pressure constant (R = 0.0831 liter * bars/mole * K), and T signifying the temperature in Kelvin (273 + °C). A 0.15 M NaCl solution at standard atmospheric pressure and 25°C has an osmotic potential of -7.4 bars, with Na+ and Cl- yielding 2 ions (in contrast to sucrose, which counts as one). Therefore, i = 2, and osmosis will drive water from the 0.1 to the 0.15 concentration.
Answer:
Yes, monazite might be present.
This mineral could have become integrated into sedimentary rock due to its formation during the metamorphosis of clastic sedimentary rocks. It is a resilient mineral discovered in debris from weathered rocks where it accumulates within the soils and sediments nearby.
Explanation:
Monazite refers to phosphate minerals typically found in small grains as secondary components in both igneous rocks and sedimentary formations. It emerges during the crystallization of igneous rocks and the metamorphosis of clastic sedimentary rocks.
Moreover, it is a tough mineral that arises in weathered rock debris and becomes concentrated in sediments that are located close to weathered rocks.
Greetings!
Answer: C. Squamous epithelial tissue.
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- Hannah ❤
