Answer:
To find the number of genuine solutions for a system of equations consisting of a linear equation and a quadratic equation
1) With two variables, say x and y, rearrange the linear equation to express y, then substitute this y in the quadratic equation
After that, simplify the resulting equation and determine the number of real roots utilizing the quadratic formula, 
for equations of the type 0 = a·x² - b·x + c.
When b² exceeds 4·a·c, two real solutions emerge; if b² equals 4·a·c, there will be a single solution.
Step-by-step explanation:
a=2+6t, b=10+2t
a=b when
2+6t=10+2t subtract 2t from both sides
2+4t=10 subtract 2 from both sides
4t=8 divide both sides by 4
t=2
Thus, they will have the same amount of snowfall after two hours
hope i helped
Arrange them starting from the smallest to the largest.
Important details about isosceles triangle ABC:
- The median CD, which is drawn to the base AB, also acts as an altitude to that base in the isosceles triangle (CD⊥AB). This indicates that triangles ACD and BCD are congruent right triangles, each with hypotenuses AC and BC.
- In isosceles triangle ABC, the sides AB and BC are equal, meaning AC=BC.
- The base angles at AB are equal, m∠A=m∠B=30°.
1. Consider the right triangle ACD. The angle adjacent to side AD is 30°, which dictates that the hypotenuse AC is double the length of the opposite side CD relating to angle A.
AC=2CD.
2. Now, for right triangle BCD, the angle next to side BD is also 30°, so hypotenuse BC is twice the opposite leg CD linked to angle B.
BC=2CD.
3. To calculate the perimeters of triangles ACD, BCD, and ABC:
4. If the total of the perimeters of triangles ACD and BCD is 20 cm greater than the perimeter of triangle ABC, then
5. Given that AC=BC=2CD, the lengths of legs AC and BC of the isosceles triangles are 20 cm.
Answer: 20 cm.
