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Dmitry
2 months ago
13

At what point of the curve y = cosh(x does the tangent have slope 2?

Mathematics
1 answer:
Svet_ta [12.7K]2 months ago
5 0
The hyperbolic cosine function (cosh) is defined as
cosh (x) = (e^x + e^-x) / 2
The tangent line's slope at any given point on a function is determined by the derivative of that function at that specific point.
d/dx [cosh(x)] = d/dx[(e^x + e^-x) / 2] = (e^x - e^-x) / 2 = sinh(x)
Assuming the slope equals 2, we have
sinh(x) = 2
thus,
x = sinh^-1 (2) = 1.444
Consequently, the curve of y = cosh(x) has a slope of 2 at the coordinate x = 1.44
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3 months ago
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To determine which functions depict the arithmetic sequence 8, 1.5, -5, -11.5,... follow these steps:

<span>f(n) = –6.5n + 14.5... correct
f(1) = 8
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f(3) = -5
f(4) = -11.5

f(n) = –1.5n + 9.5... incorrect
f(1) = 8
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f(n) = 6.5n + 1.5... incorrect
f(1) = 8
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f(1) = 8, f(n + 1) = f(n) – 6.5... correct
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f(3) = 1.5 - 6.5 = -5
f(4) = -5 - 6.5 = -11.5

f(1) = 8, f(n + 1) = f(n) – 1.5... incorrect
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f(1) = 8, f(n + 1) = f(n) + 6.5... incorrect
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The valid functions are:
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