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Whitepunk
4 days ago
7

Kevin is buying water for his camping trip. He knows he needs at least 20 gallons of water for the trip. He already has five and

a half gallons. The water comes in 32-fluid ounce (quarter-gallon) containers. What algebraic inequality represents this situation?
Mathematics
2 answers:
Inessa [8.9K]4 days ago
5 0

Response: One-fourth x plus five and one-half is greater-than-or-equal-to 20

Step-by-step explanation:

PIT_PIT [9.1K]4 days ago
5 0

Response:

5.5+0.25x\geq 20

Step-by-step breakdown:

Kevin has already gathered five and a half gallons of water for his trip

He understands that he requires a minimum of 20 gallons of water for the journey.

The water is packaged in 32-fluid ounce (quarter-gallon) containers.

1 fluid ounce equals 0.0078125 gallons

32-fluid ounce =32 \times 0.0078125 =0.25

Let x represent the number of 32-fluid ounce (quarter-gallon) containers needed to collect at least 20 gallons of water for the trip.

One container holds 0.25 gallons of water

Therefore, x containers hold 0.25x gallons of water

Thus, Kevin's total gallons of water =5.5+0.25x

Since it is given that he needs at least 20 gallons of water for the trip.

Hence, 5.5+0.25x\geq 20

Thus, the algebraic inequality representing this scenario is 5.5+0.25x\geq 20

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Answer:

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Explanation:

Geometry has three undefined terms:

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Examining the given statements:

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2) A plane has clear start and end points — this is false as a plane extends infinitely without boundaries.

3) A line has exactly one dimension, which is its length. (True)

4) A point consists of countless lines — this is false; actually, a line consists of infinite points.

5) A plane consists of an unending set of lines. (True)

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An angle bisector always creates two acute angles. find a counterexample to show that the conjecture is false.
Inessa [8989]
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If 25 dimes were moved from Box A to Box B, there would be an equal amount of dimes in both boxes. If 100 dimes were moved from
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First note the ratio is
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11 days ago
In a cash drawer there is $125 in $5 and $10 bills. The number of $10 bills is twice the number of $5 bills. How many of each ty
AnnZ [9071]
Let x denote the count of $5 bills and y signify the count of $10 bills. It can be stated that "the number of $10 bills is twice the number of $5 bills." Thus, y is 2 times x. We can formulate an equation, y = 2x (equation 1). The total value of all bills amounts to $125, allowing us to create another equation: 5*(number of $5 bills) + 10*(number of $10 bills) = 125. That leads to the equation 5(x) + 10(y) = 125 (equation 2). By substituting y = 2x into equation 2, we get 5(x) + 10(2x) = 125. This simplifies to 5x + 20x = 125. Combining like terms yields 25x = 125. Dividing both sides by 25 results in x = 5. By substituting x = 5 in the first equation, we find y = 2(5) = 10. Consequently, there are 5 $5 bills and 10 $10 bills.
5 0
3 days ago
Turkey sandwiches cost $2.50 and veggie wraps cost $3.50 at a snack stand. Ben has sold no more than $30 worth of turkey sandwic
tester [8808]

Answer:

Ben could have sold a maximum of 6 turkey sandwiches.

Step-by-step explanation:

Turkey sandwiches are priced at $2.50, while veggie wraps cost $3.50 at the snack stand.

Our goal is to determine the largest number of turkey sandwiches Ben might have sold.

2. 5 0 x + 3. 5 0 y \leq 3 0

4 veggie wraps were sold (y).

Thus, the inequality is: 2.50x + 3.50(4) < 30

2.50x + 14 < 30

- 14 - 14

2.50x < 16

x

x

Ultimately, Ben could sell a maximum of 6 turkey sandwiches.

4 0
1 month ago
Read 2 more answers
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