I believe the answer is D, though I'm not entirely certain unfortunately.
Laws of Nature should be differentiated from Scientific and Natural Laws. The Necessitarian Theory suggests that Laws of Nature are those principles which influence the natural phenomena in the universe, meaning the natural world adheres to them.
Calculation yields 209.53. The molar concentration is calculated by moles divided by volume. Given the volume of 750 mL, which translates to 0.75 L, the moles of CuBr₂ can be determined as molar concentration multiplied by volume, resulting in 1.25 × 0.75 = 0.9375. Mole count is derived from the mass of CuBr₂ divided by its molecular mass. The molecular mass of CuBr₂ is computed as 63.5 + 80 × 2 = 223.5, where the mass of Cu is 63.5 and that of Br is 80. Consequently, the mass needed amounts to 223.5 × 0.9375 = 209.53 g.
The molar masses for H2S and NH3 are 34 and 17 g/mol, respectively. The appropriate equation to represent this is,
Rate A/Rate B = √(molar mass B/molar mass A)
Substituting values,
x/77 = √(17 /34 )
x = 54.4
This means NH3 will take 54.4 seconds to escape through the container.
Answer: The enthalpy change for the reaction is, 201.9 kJ
Explanation:
Based on Hess’s law of constant heat summation, the energy released or absorbed in a chemical reaction stays constant, regardless of whether the process unfolds in one step or multiple steps.
This principle implies, that chemical equations can be treated analogously to algebraic expressions, allowing addition or subtraction to create the needed equation. Thus, the overall enthalpy change corresponds to the summation of the individual enthalpy changes of the reactions occurring in between.
The balanced equation for
appears as follows,

The intermediate balanced reactions are outlined as follows,
(1)

(2)

(3)

(4)

Next, we will multiply the first reaction by 2, reverse the second, and reverse and halve the third and fourth reactions before combining them. This gives us:
(1)

(2)

(3)

(4)

Therefore, the expression for the enthalpy of the reaction is,



Hence, the enthalpy change for this reaction is, 201.9 kJ